A) \[{{K}_{P}}={{P}_{CO}}_{2}\]
B) \[{{K}_{P}}=Pc{{o}_{2}}\times \frac{Pc{{o}_{2}}\times {{P}_{MgO}}}{{{P}_{MgC{{O}_{3}}}}}\]
C) \[K{}_{P}=\frac{Pc{{o}_{2}}\times {{P}_{MgO}}}{{{P}_{MgC{{O}_{3}}}}}\]
D) \[{{K}_{P}}=\frac{{{P}_{MgC{{O}_{3}}}}}{{{P}_{C{{O}_{2}}}}\times {{P}_{MgO}}}\]
Correct Answer: A
Solution :
In this reaction gaseous molecule count \[MgC{{O}_{3}}\to Mg{{O}_{(s)}}+C{{O}_{2(g)}}\] \[{{K}_{p}}={{P}_{C{{O}_{2}}}}\]You need to login to perform this action.
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