A) \[1.95\times {{10}^{-3}}\]
B) \[1.95\times {{10}^{3}}\]
C) \[7.5\times {{10}^{2}}\]
D) \[0.9\times {{10}^{6}}\]
Correct Answer: C
Solution :
\[{{K}_{{{c}_{1}}}}=\frac{{{[NO]}^{2}}[{{O}_{2}}]}{{{[N{{O}_{2}}]}^{2}}}=1.8\times {{10}^{-6}}\]Þ \[{{K}_{{{c}_{2}}}}=\frac{[N{{O}_{2}}]}{[NO]\,\,{{[{{O}_{2}}]}^{{1}/{2}\;}}}\] \[{{K}_{{{c}_{1}}}}=\frac{1}{K_{{{c}_{2}}}^{2}}\]; \[1.8\times {{10}^{-6}}=\frac{1}{{{K}_{{{c}_{2}}}}^{2}}\]Þ\[{{K}_{{{c}_{2}}}}=7.5\times {{10}^{2}}\]You need to login to perform this action.
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