JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Kp and Kc Relationship and Characteristics of K

  • question_answer
    If \[{{K}_{c}}\] is the equilibrium constant for the formation of \[N{{H}_{3}}\], the dissociation constant of ammonia under the same temperature will be    [DPMT 2001]

    A)  \[{{K}_{c}}\]     

    B)                 \[\sqrt{{{K}_{c}}}\]

    C)                 \[K_{c}^{2}\]     

    D)                 \[1/{{K}_{c}}\]

    Correct Answer: D

    Solution :

             \[N{{H}_{3}}\]⇌ \[\frac{1}{2}{{N}_{2}}+\frac{3}{2}{{H}_{2}}\]            \[{{K}_{c}}=\frac{{{[{{N}_{2}}]}^{{1}/{2}\;}}{{[{{H}_{2}}]}^{{3}/{2}\;}}}{N{{H}_{3}}}\] and           \[\frac{1}{2}{{N}_{2}}+\frac{3}{2}{{H}_{2}}\]⇌\[N{{H}_{3}}\]            \[{{K}_{c}}=\frac{[N{{H}_{3}}]}{{{[{{N}_{2}}]}^{{1}/{2}\;}}{{[{{H}_{2}}]}^{{3}/{2}\;}}}\]                  So for dissociation\[=\frac{1}{{{K}_{c}}}\]


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