JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Kp and Kc Relationship and Characteristics of K

  • question_answer
    The equilibrium constant for the reaction \[{{N}_{2}}+3{{H}_{2}}\]⇌\[2N{{H}_{3}}\] is \[K,\] then the equilibrium constant for the equilibrium \[N{{H}_{3}}\]⇌\[\frac{1}{2}{{N}_{2}}+\frac{3}{2}{{H}_{2}}\] is [CBSE PMT 1996; UPSEAT 2001]

    A)                 \[1/K\]

    B)                 \[1/{{K}^{2}}\]

    C)                 \[\sqrt{K}\]        

    D)                 \[\frac{1}{\sqrt{K}}\]

    Correct Answer: D

    Solution :

               \[{{K}_{1}}\] for \[{{N}_{2}}+3{{H}_{2}}\] ⇌ \[2N{{H}_{3}}\]                    \[{{K}_{2}}\] for \[N{{H}_{3}}\] ⇌ \[\frac{1}{2}{{N}_{2}}+\frac{3}{2}{{H}_{2}}\]                \[{{K}_{1}}\times {{K}_{2}}=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]\,\,{{[{{H}_{2}}]}^{3}}}\times \frac{{{[{{N}_{2}}]}^{{1}/{2}\;}}{{[{{H}_{2}}]}^{{3}/{2}\;}}}{[N{{H}_{3}}]}\]                                 \[{{K}_{1}}\times {{K}_{2}}=\frac{1}{{{K}_{2}}}\];  \[{{K}_{2}}=\frac{1}{\sqrt{{{K}_{1}}}}\]


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