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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Kp and Kc Relationship and Characteristics of K

  • question_answer
    At a given temperature, the equilibrium constant for reaction \[PC{{l}_{5}}(g)\]⇌ \[PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] is \[2.4\times {{10}^{-3}}\]. At the same temperature, the equilibrium constant for reaction \[PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] ⇌ \[PC{{l}_{5}}(g)\] is          [KCET 1992]

    A)                 \[2.4\times {{10}^{-3}}\]              

    B)                 \[-2.4\times {{10}^{-3}}\]

    C)                 \[4.2\times {{10}^{2}}\]                

    D)                 \[4.8\times {{10}^{-2}}\]

    Correct Answer: C

    Solution :

           Reaction is reversed. Hence                                 \[K=\frac{1}{(2.4\times {{10}^{-3}})}=4.2\times {{10}^{2}}\]


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