JEE Main & Advanced Mathematics Mathematical Logic and Boolean Algebra Question Bank

done Critical Thinking Total Questions - 5

• question_answer1)
  Negation of the proposition: If we control population growth, we prosper
  A)
  If we do not control population growth, we prosper done clear
  B)
  It we control population growth, we do not prosper done clear
  C)
  We control population but we do not prosper done clear
  D)
  We do not control population, but we prosper done clear
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• question_answer2)
  Which Venn diagram represent the truth of the statement. All smokers are drinkers and all drinkers are smokers.
  A)
                  done clear
  B)
    done clear
  C)
                 done clear
  D)
  None of these done clear
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• question_answer3)
  For the circuits shown below, the Boolean polynomial is  [Karnataka CET 1999]
  A)
  \[(\tilde{\ }p\vee q)\vee (p\ \vee \tilde{\ }q)\] done clear
  B)
  \[(\tilde{\ }p\wedge p)\wedge (q\wedge q)\] done clear
  C)
  \[(\tilde{\ }p\ \wedge \tilde{\ }q)\wedge (q\wedge p)\] done clear
  D)
  \[(\tilde{\ }p\wedge q)\vee (p\ \wedge \tilde{\ }q)\] done clear
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• question_answer4)
  Let p be the proposition : Mathematics is a interesting and let q be the propositions that Mathematics is difficult, then the symbol \[p\wedge q\] means [Karnataka CET 2001]
  A)
  Mathematics is interesting implies that Mathematics is difficult done clear
  B)
  Mathematics is interesting implies and is implied by Mathematics is difficult done clear
  C)
  Mathematics is interesting and Mathematics is difficult done clear
  D)
  Mathematics is interesting or Mathematics is difficult done clear
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• question_answer5)
  An AND gate is the Boolean function defined by
  A)
  \[f({{x}_{1}},\,{{x}_{2}})={{x}_{1}}:\,{{x}_{2}},\,\,\,\,{{x}_{1}},\,{{x}_{2}}\in \{0,\,1\}\] done clear
  B)
  \[f({{x}_{1}},\,{{x}_{2}})={{x}_{1}}+\,{{x}_{2}},\,\,\,\,{{x}_{1}},\,{{x}_{2}}\in \{0,\,1\}\] done clear
  C)
  \[f({{x}_{1}},\,{{x}_{2}})={{x}_{1}},\,\,\,\,\,\,\,\,\,\,\,\,\,{{x}_{1}},\,{{x}_{2}}\in \{0,\,1\}\] done clear
  D)
  \[f({{x}_{1}},\,{{x}_{2}})={{x}_{2}},\,\,\,\,\,\,\,\,\,\,\,\,\,{{x}_{1}},\,{{x}_{2}}\in \{0,\,1\}\] done clear
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