-
question_answer1)
If \[{{\cos }^{-1}}\left( \frac{1}{x} \right)=\theta \], then \[\tan \theta \]= [MNR 1978; MP PET 1989]
A)
\[\frac{1}{\sqrt{{{x}^{2}}-1}}\] done
clear
B)
\[\sqrt{{{x}^{2}}+1}\] done
clear
C)
\[\sqrt{1-{{x}^{2}}}\] done
clear
D)
\[\sqrt{{{x}^{2}}-1}\] done
clear
View Solution play_arrow
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question_answer2)
\[\sin ({{\cot }^{-1}}x)\] [MNR 1987; MP PET 2001; DCE 2002]
A)
\[\sqrt{1+{{x}^{2}}}\] done
clear
B)
\[x\] done
clear
C)
\[{{(1+{{x}^{2}})}^{-3/2}}\] done
clear
D)
\[{{(1+{{x}^{2}})}^{-1/2}}\] done
clear
View Solution play_arrow
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question_answer3)
\[\cos \text{ }\left( {{\sin }^{-1}}\frac{5}{13} \right)=\]
A)
\[\frac{12}{13}\] done
clear
B)
\[-\frac{12}{13}\] done
clear
C)
\[\frac{5}{12}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer4)
\[{{\cot }^{-1}}(-\sqrt{3})\]=
A)
\[-\frac{\pi }{6}\] done
clear
B)
\[\frac{5\pi }{6}\] done
clear
C)
\[\frac{\pi }{3}\] done
clear
D)
\[\frac{2\pi }{3}\] done
clear
View Solution play_arrow
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question_answer5)
\[1+{{\cot }^{2}}({{\sin }^{-1}}x)=\]
A)
\[\frac{1}{2x}\] done
clear
B)
\[{{x}^{2}}\] done
clear
C)
\[\frac{1}{{{x}^{2}}}\] done
clear
D)
\[\frac{2}{x}\] done
clear
View Solution play_arrow
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question_answer6)
If \[{{\sin }^{-1}}\frac{1}{2}={{\tan }^{-1}}x,\]then x =
A)
\[\sqrt{3}\] done
clear
B)
\[\frac{1}{\sqrt{3}}\] done
clear
C)
\[\frac{1}{\sqrt{2}}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer7)
\[{{\tan }^{-1}}\left( \frac{\sqrt{1+{{x}^{2}}}-1}{x} \right)=\]
A)
\[{{\tan }^{-1}}x\] done
clear
B)
\[\frac{1}{2}{{\tan }^{-1}}x\] done
clear
C)
\[2{{\tan }^{-1}}x\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer8)
\[{{\tan }^{-1}}\frac{x}{\sqrt{{{a}^{2}}-{{x}^{2}}}}=\]
A)
\[\frac{1}{a}{{\sin }^{-1}}\left( \frac{x}{a} \right)\] done
clear
B)
\[a{{\sin }^{-1}}\left( \frac{x}{a} \right)\] done
clear
C)
\[{{\sin }^{-1}}\left( \frac{x}{a} \right)\] done
clear
D)
\[{{\sin }^{-1}}\left( \frac{a}{x} \right)\] done
clear
View Solution play_arrow
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question_answer9)
During \[\cos ({{\tan }^{-1}}x)=\] [MP PET 1988; MNR 1981]
A)
\[\sqrt{1+{{x}^{2}}}\] done
clear
B)
\[\frac{1}{\sqrt{1+{{x}^{2}}}}\] done
clear
C)
\[1+{{x}^{2}}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer10)
\[\tan \left[ {{\sec }^{-1}}\sqrt{1+{{x}^{2}}} \right]=\]
A)
\[\frac{1}{x}\] done
clear
B)
x done
clear
C)
\[\frac{1}{\sqrt{1+{{x}^{2}}}}\] done
clear
D)
\[\frac{x}{\sqrt{1+{{x}^{2}}}}\] done
clear
View Solution play_arrow
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question_answer11)
\[{{\sec }^{-1}}[\sec (-{{30}^{o}})]=\] [MP PET 1992]
A)
\[-{{60}^{o}}\] done
clear
B)
\[-{{30}^{o}}\] done
clear
C)
\[{{30}^{o}}\] done
clear
D)
\[{{150}^{o}}\] done
clear
View Solution play_arrow
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question_answer12)
\[{{\tan }^{-1}}\left[ \frac{\cos x}{1+\sin x} \right]=\]
A)
\[\frac{\pi }{4}-\frac{x}{2}\] done
clear
B)
\[\frac{\pi }{4}+\frac{x}{2}\] done
clear
C)
\[\frac{x}{2}\] done
clear
D)
\[\frac{\pi }{4}-x\] done
clear
View Solution play_arrow
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question_answer13)
\[{{\tan }^{-1}}\frac{1}{\sqrt{{{x}^{2}}-1}}=\]
A)
\[\frac{\pi }{2}+\text{cose}{{\text{c}}^{-1}}x\] done
clear
B)
\[\frac{\pi }{2}+{{\sec }^{-1}}x\] done
clear
C)
\[\text{cose}{{\text{c}}^{-1}}x\] done
clear
D)
\[{{\sec }^{-1}}x\] done
clear
View Solution play_arrow
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question_answer14)
The principal value of \[{{\sin }^{-1}}\left( -\frac{1}{2} \right)\]is
A)
\[\frac{\pi }{3}\] done
clear
B)
\[\frac{\pi }{6}\] done
clear
C)
\[-\frac{\pi }{3}\] done
clear
D)
\[-\frac{\pi }{6}\] done
clear
View Solution play_arrow
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question_answer15)
\[{{\sec }^{2}}({{\tan }^{-1}}2)+\text{cose}{{\text{c}}^{2}}({{\cot }^{-1}}3)=\] [EAMCET 2001]
A)
5 done
clear
B)
13 done
clear
C)
15 done
clear
D)
6 done
clear
View Solution play_arrow
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question_answer16)
\[{{\sin }^{-1}}\left[ x\sqrt{1-x}-\sqrt{x}\sqrt{1-{{x}^{2}}} \right]=\]
A)
\[{{\sin }^{-1}}x+{{\sin }^{-1}}\sqrt{x}\] done
clear
B)
\[{{\sin }^{-1}}x-{{\sin }^{-1}}\sqrt{x}\] done
clear
C)
\[{{\sin }^{-1}}\sqrt{x}-{{\sin }^{-1}}x\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer17)
If \[{{\tan }^{-1}}\frac{1-x}{1+x}=\frac{1}{2}{{\tan }^{-1}}x\], then x =
A)
1 done
clear
B)
\[\sqrt{3}\] done
clear
C)
\[\frac{1}{\sqrt{3}}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer18)
\[{{\cos }^{-1}}\left( \cos \frac{7\pi }{6} \right)=\]
A)
\[\frac{7\pi }{6}\] done
clear
B)
\[\frac{5\pi }{6}\] done
clear
C)
\[\frac{\pi }{6}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer19)
The value of \[\sin {{\cot }^{-1}}\tan {{\cos }^{-1}}x\]is equal to [Bihar CEE 1974]
A)
x done
clear
B)
\[\frac{\pi }{2}\] done
clear
C)
1 done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer20)
\[{{\sin }^{-1}}\frac{\sqrt{x}}{\sqrt{x+a}}\]is equal to
A)
\[{{\cos }^{-1}}\sqrt{\frac{x}{a}}\] done
clear
B)
\[\text{cose}{{\text{c}}^{-1}}\sqrt{\frac{x}{a}}\] done
clear
C)
\[{{\tan }^{-1}}\sqrt{\frac{x}{a}}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer21)
If \[\sin \left( {{\sin }^{-1}}\frac{1}{5}+{{\cos }^{-1}}x \right)=1\],then x is equal to [MNR 1994; Kerala (Engg.) 2005]
A)
1 done
clear
B)
0 done
clear
C)
\[\frac{4}{5}\] done
clear
D)
\[\frac{1}{5}\] done
clear
View Solution play_arrow
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question_answer22)
If \[{{\sin }^{-1}}x=\theta +\beta \]and \[{{\sin }^{-1}}y=\theta -\beta ,\]then \[1+xy=\]
A)
\[{{\sin }^{2}}\theta +{{\sin }^{2}}\beta \] done
clear
B)
\[{{\sin }^{2}}\theta +{{\cos }^{2}}\beta \] done
clear
C)
\[{{\cos }^{2}}\theta +{{\cos }^{2}}\beta \] done
clear
D)
\[{{\cos }^{2}}\theta +{{\sin }^{2}}\beta \] done
clear
View Solution play_arrow
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question_answer23)
If \[{{\sin }^{-1}}\frac{1}{3}+{{\sin }^{-1}}\frac{2}{3}={{\sin }^{-1}}x,\]then x is equal to [Roorkee 1995]
A)
0 done
clear
B)
\[\frac{\sqrt{5}-4\sqrt{2}}{9}\] done
clear
C)
\[\frac{\sqrt{5}+4\sqrt{2}}{9}\] done
clear
D)
\[\frac{\pi }{2}\] done
clear
View Solution play_arrow
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question_answer24)
\[\tan ({{\cos }^{-1}}x)\] is equal to [IIT 1993]
A)
\[\frac{\sqrt{1-{{x}^{2}}}}{x}\] done
clear
B)
\[\frac{x}{1+{{x}^{2}}}\] done
clear
C)
\[\frac{\sqrt{1+{{x}^{2}}}}{x}\] done
clear
D)
\[\sqrt{1-{{x}^{2}}}\] done
clear
View Solution play_arrow
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question_answer25)
The domain of \[{{\sin }^{-1}}x\]is [Roorkee 1993]
A)
\[(-\pi ,\pi )\] done
clear
B)
[-1, 1] done
clear
C)
\[(0,\,2\pi )\] done
clear
D)
\[(-\infty ,\,\infty )\] done
clear
View Solution play_arrow
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question_answer26)
The principal value of \[{{\sin }^{-1}}\left( -\,\,\frac{\sqrt{3}}{2} \right)\]is [Roorkee 1992]
A)
\[\frac{-2\pi }{3}\] done
clear
B)
\[\frac{-\pi }{3}\] done
clear
C)
\[\frac{-2\pi }{3}\] done
clear
D)
\[\frac{5\pi }{3}\] done
clear
View Solution play_arrow
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question_answer27)
\[\cot \,\,\left[ {{\cos }^{-1}}\left( \frac{7}{25} \right) \right]=\] [Karnataka CET 1994]
A)
\[\frac{25}{24}\] done
clear
B)
\[\frac{25}{7}\] done
clear
C)
\[\frac{24}{25}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer28)
If \[\frac{\pi }{2}\le x\le \frac{3\pi }{2},\]then\[{{\sin }^{-1}}(\sin x)\]is equal to
A)
x done
clear
B)
\[-x\] done
clear
C)
\[\pi +x\] done
clear
D)
\[\pi -x\] done
clear
View Solution play_arrow
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question_answer29)
If \[\pi \le x\le 2\pi \], then \[{{\cos }^{-1}}(\cos x)\]is equal to
A)
x done
clear
B)
\[-x\] done
clear
C)
\[2\pi +x\] done
clear
D)
\[2\pi -x\] done
clear
View Solution play_arrow
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question_answer30)
The value of \[{{\sin }^{-1}}(\sin 10)\]is
A)
10 done
clear
B)
\[10-3\pi \] done
clear
C)
\[3\pi -10\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer31)
The smallest and the largest values of \[{{\tan }^{-1}}\left( \frac{1-x}{1+x} \right)\text{ },\,\,0\le x\le 1\]are
A)
\[0,\,\,\pi \] done
clear
B)
\[0,\,\frac{\pi }{4}\] done
clear
C)
\[-\frac{\pi }{4},\frac{\pi }{4}\] done
clear
D)
\[\frac{\pi }{4},\,\frac{\pi }{2}\] done
clear
View Solution play_arrow
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question_answer32)
If \[x\]takes non-positive permissible value, then \[{{\sin }^{-1}}x\]=
A)
\[{{\cos }^{-1}}\sqrt{1-{{x}^{2}}}\] done
clear
B)
\[-{{\cos }^{-1}}\sqrt{1-{{x}^{2}}}\] done
clear
C)
\[{{\cos }^{-1}}\sqrt{{{x}^{2}}-1}\] done
clear
D)
\[\pi -{{\cos }^{-1}}\sqrt{1-{{x}^{2}}}\] done
clear
View Solution play_arrow
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question_answer33)
\[{{\left[ \sin \left( {{\tan }^{-1}}\frac{3}{4} \right) \right]}^{2}}=\] [EAMCET 1983]
A)
\[\frac{3}{5}\] done
clear
B)
\[\frac{5}{3}\] done
clear
C)
\[\frac{9}{25}\] done
clear
D)
\[\frac{25}{9}\] done
clear
View Solution play_arrow
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question_answer34)
The principal value of \[{{\sin }^{-1}}\left( \sin \frac{5\pi }{3} \right)\]is [MP PET 1996]
A)
\[\frac{5\pi }{3}\] done
clear
B)
\[-\frac{5\pi }{3}\] done
clear
C)
\[-\frac{\pi }{3}\] done
clear
D)
\[\frac{4\pi }{3}\] done
clear
View Solution play_arrow
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question_answer35)
The value of x which satisfies the equation \[{{\tan }^{-1}}x=\] \[{{\sin }^{-1}}\left( \frac{3}{\sqrt{10}} \right)\] is [Pb. CET 1999]
A)
3 done
clear
B)
-3 done
clear
C)
\[\frac{1}{3}\] done
clear
D)
\[-\frac{1}{3}\] done
clear
View Solution play_arrow
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question_answer36)
\[\sec (\text{cose}{{\text{c}}^{-1}}x)\] is equal to [Kurukshetra CEE 2001]
A)
\[\text{cosec}({{\sec }^{-1}}x)\] done
clear
B)
\[\cot x\] done
clear
C)
\[\pi \] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer37)
The range of \[{{\tan }^{-1}}\]x is [DCE 2002]
A)
\[\left( \pi ,\frac{\pi }{2} \right)\] done
clear
B)
\[\left( -\frac{\pi }{2},\frac{\pi }{2} \right)\] done
clear
C)
\[(-\pi ,\,\,\pi )\] done
clear
D)
\[(0,\pi )\] done
clear
View Solution play_arrow
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question_answer38)
If \[\theta ={{\sin }^{-1}}[\sin (-{{600}^{o}})]\], then one of the possible value of \[\theta \]is [Kerala (Engg.) 2002]
A)
\[\frac{\pi }{3}\] done
clear
B)
\[\frac{\pi }{2}\] done
clear
C)
\[\frac{2\pi }{3}\] done
clear
D)
\[\frac{-2\pi }{3}\] done
clear
View Solution play_arrow
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question_answer39)
The solution set of the equation \[{{\sin }^{-1}}x=2{{\tan }^{-1}}x\] is [AMU 2002]
A)
{1, 2} done
clear
B)
{-1, 2} done
clear
C)
{-1, 1, 0} done
clear
D)
{1, 1/2, 0} done
clear
View Solution play_arrow
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question_answer40)
The value of \[\cos ({{\tan }^{-1}}(\tan 2))\]is [AMU 2002]
A)
\[\frac{1}{\sqrt{5}}\] done
clear
B)
\[-\frac{1}{\sqrt{5}}\] done
clear
C)
\[\cos \,2\] done
clear
D)
\[-\cos 2\] done
clear
View Solution play_arrow
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question_answer41)
If \[{{\sin }^{-1}}x+{{\sin }^{-1}}y+{{\sin }^{-1}}z=\frac{\pi }{2}\], then the value of \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}+2xyz\]is equal to [Pb. CET 2002]
A)
0 done
clear
B)
1 done
clear
C)
2 done
clear
D)
3 done
clear
View Solution play_arrow
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question_answer42)
\[\sin \left[ \frac{\pi }{2}-{{\sin }^{-1}}\left( -\frac{\sqrt{3}}{2} \right) \right]=\]
A)
\[\frac{\sqrt{3}}{2}\] done
clear
B)
\[-\frac{\sqrt{3}}{2}\] done
clear
C)
\[\frac{1}{2}\] done
clear
D)
\[-\frac{1}{2}\] done
clear
View Solution play_arrow
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question_answer43)
\[\sin [{{\cot }^{-1}}(\cos {{\tan }^{-1}}x)]\]=
A)
\[\frac{x}{\sqrt{{{x}^{2}}+2}}\] done
clear
B)
\[\frac{x}{\sqrt{{{x}^{2}}+1}}\] done
clear
C)
\[\frac{1}{\sqrt{{{x}^{2}}+2}}\] done
clear
D)
\[\sqrt{\frac{{{x}^{2}}+1}{{{x}^{2}}+2}}\] done
clear
View Solution play_arrow
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question_answer44)
If \[\sin ({{\cot }^{-1}}(x+1)=\cos ({{\tan }^{-1}}x)\], then x = [IIT Screening 2004]
A)
\[-\frac{1}{2}\] done
clear
B)
\[\frac{1}{2}\] done
clear
C)
0 done
clear
D)
\[\frac{9}{4}\] done
clear
View Solution play_arrow
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question_answer45)
\[{{\cos }^{-1}}\frac{4}{5}+{{\tan }^{-1}}\frac{3}{5}=\]
A)
\[{{\tan }^{-1}}\frac{27}{11}\] done
clear
B)
\[{{\sin }^{-1}}\frac{11}{27}\] done
clear
C)
\[{{\cos }^{-1}}\frac{11}{27}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer46)
\[{{\sin }^{-1}}x+{{\sin }^{-1}}\frac{1}{x}+{{\cos }^{-1}}x+{{\cos }^{-1}}\frac{1}{x}=\]
A)
\[\pi \] done
clear
B)
\[\frac{\pi }{2}\] done
clear
C)
\[\frac{3\pi }{2}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer47)
\[2{{\tan }^{-1}}\frac{1}{3}+{{\tan }^{-1}}\frac{1}{2}=\]
A)
\[{{90}^{o}}\] done
clear
B)
\[{{60}^{o}}\] done
clear
C)
\[{{45}^{o}}\] done
clear
D)
\[{{\tan }^{-1}}2\] done
clear
View Solution play_arrow
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question_answer48)
\[\tan \left( {{90}^{o}}-{{\cot }^{-1}}\frac{1}{3} \right)=\]
A)
3 done
clear
B)
\[\frac{2}{3}\] done
clear
C)
\[\frac{1}{3}\] done
clear
D)
\[\frac{1}{\sqrt{10}}\] done
clear
View Solution play_arrow
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question_answer49)
\[\tan \left[ {{\cos }^{-1}}\frac{4}{5}+{{\tan }^{-1}}\frac{2}{3} \right]\]= [IIT 1983; EAMCET 1988; MP PET 1990; MNR 1992]
A)
6/17 done
clear
B)
17/6 done
clear
C)
7/16 done
clear
D)
16/7 done
clear
View Solution play_arrow
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question_answer50)
\[{{\tan }^{-1}}1+{{\tan }^{-1}}2+{{\tan }^{-1}}3=\]
A)
\[\frac{\pi }{2}\] done
clear
B)
\[\frac{\pi }{4}\] done
clear
C)
0 done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer51)
\[{{\cot }^{-1}}\frac{3}{4}+{{\sin }^{-1}}\frac{5}{13}=\]
A)
\[{{\sin }^{-1}}\frac{63}{65}\] done
clear
B)
\[{{\sin }^{-1}}\frac{12}{13}\] done
clear
C)
\[{{\sin }^{-1}}\frac{65}{68}\] done
clear
D)
\[{{\sin }^{-1}}\frac{5}{12}\] done
clear
View Solution play_arrow
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question_answer52)
If \[{{\cos }^{-1}}x+{{\cos }^{-1}}y+{{\cos }^{-1}}z=\pi \], then [Roorkee 1994]
A)
\[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}+xyz=0\] done
clear
B)
\[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}+2xyz=0\] done
clear
C)
\[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}+xyz=1\] done
clear
D)
\[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}+2xyz=1\] done
clear
View Solution play_arrow
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question_answer53)
If \[{{\tan }^{-1}}x-{{\tan }^{-1}}y={{\tan }^{-1}}A,\]then A = [MP PET 1988]
A)
\[x-y\] done
clear
B)
\[x+y\] done
clear
C)
\[\frac{x-y}{1+xy}\] done
clear
D)
\[\frac{x+y}{1-xy}\] done
clear
View Solution play_arrow
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question_answer54)
If \[{{\tan }^{-1}}x+{{\tan }^{-1}}y+{{\tan }^{-1}}z=\frac{\pi }{2},\]then [Karnataka CET 1996]
A)
\[x+y+z-xyz=0\] done
clear
B)
\[x+y+z+xyz=0\] done
clear
C)
\[xy+yz+zx+1=0\] done
clear
D)
\[xy+yz+zx-1=0\] done
clear
View Solution play_arrow
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question_answer55)
If \[{{\tan }^{-1}}\frac{x-1}{x+2}+{{\tan }^{-1}}\frac{x+1}{x+2}=\frac{\pi }{4}\], then x =
A)
\[\frac{1}{\sqrt{2}}\] done
clear
B)
\[-\frac{1}{\sqrt{2}}\] done
clear
C)
\[\pm \sqrt{\frac{5}{2}}\] done
clear
D)
\[\pm \frac{1}{2}\] done
clear
View Solution play_arrow
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question_answer56)
\[{{\cos }^{-1}}\sqrt{1-x}+{{\sin }^{-1}}\sqrt{1-x}=\]
A)
\[\pi \] done
clear
B)
\[\frac{\pi }{2}\] done
clear
C)
1 done
clear
D)
0 done
clear
View Solution play_arrow
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question_answer57)
\[\cos \left[ 2{{\cos }^{-1}}\frac{1}{5}+{{\sin }^{-1}}\frac{1}{5} \right]=\] [IIT 1981]
A)
\[\frac{2\sqrt{6}}{5}\] done
clear
B)
\[-\frac{2\sqrt{6}}{5}\] done
clear
C)
\[\frac{1}{5}\] done
clear
D)
\[-\frac{1}{5}\] done
clear
View Solution play_arrow
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question_answer58)
\[{{\tan }^{-1}}\frac{a-b}{1+ab}+{{\tan }^{-1}}\frac{b-c}{1+bc}=\]
A)
\[{{\tan }^{-1}}a-{{\tan }^{-1}}b\] done
clear
B)
\[{{\tan }^{-1}}a-{{\tan }^{-1}}c\] done
clear
C)
\[{{\tan }^{-1}}b-{{\tan }^{-1}}c\] done
clear
D)
\[{{\tan }^{-1}}c-{{\tan }^{-1}}a\] done
clear
View Solution play_arrow
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question_answer59)
If \[{{\tan }^{-1}}2x+{{\tan }^{-1}}3x=\frac{\pi }{4}\], then x = [Roorkee 1978, 80; MNR 1986; Pb. CET 2001; Karnataka CET 2002]
A)
- 1 done
clear
B)
\[\frac{1}{6}\] done
clear
C)
\[-1,\,\frac{1}{6}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer60)
If \[{{\cot }^{-1}}x+{{\tan }^{-1}}3=\frac{\pi }{2}\], then x =
A)
1/3 done
clear
B)
1/4 done
clear
C)
3 done
clear
D)
4 done
clear
View Solution play_arrow
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question_answer61)
\[2{{\sin }^{-1}}\frac{3}{5}+{{\cos }^{-1}}\frac{24}{25}=\]
A)
\[\frac{\pi }{2}\] done
clear
B)
\[\frac{2\pi }{3}\] done
clear
C)
\[\frac{5\pi }{3}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer62)
\[\cos \left[ {{\tan }^{-1}}\frac{1}{3}+{{\tan }^{-1}}\frac{1}{2} \right]=\] [MP PET 1991; MNR 1990]
A)
\[\frac{1}{\sqrt{2}}\] done
clear
B)
\[\frac{\sqrt{3}}{2}\] done
clear
C)
\[\frac{1}{2}\] done
clear
D)
\[\frac{\pi }{4}\] done
clear
View Solution play_arrow
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question_answer63)
\[{{\tan }^{-1}}x+{{\cot }^{-1}}(x+1)=\]
A)
\[{{\tan }^{-1}}({{x}^{2}}+1)\] done
clear
B)
\[{{\tan }^{-1}}({{x}^{2}}+x)\] done
clear
C)
\[{{\tan }^{-1}}(x+1)\] done
clear
D)
\[{{\tan }^{-1}}({{x}^{2}}+x+1)\] done
clear
View Solution play_arrow
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question_answer64)
\[{{\cot }^{-1}}\frac{xy+1}{x-y}+{{\cot }^{-1}}\frac{yz+1}{y-z}+{{\cot }^{-1}}\frac{zx+1}{z-x}=\]
A)
0 done
clear
B)
1 done
clear
C)
\[{{\cot }^{-1}}x+{{\cot }^{-1}}y+{{\cot }^{-1}}z\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer65)
If \[{{\tan }^{-1}}\frac{a+x}{a}+{{\tan }^{-1}}\frac{a-x}{a}=\frac{\pi }{6}\],then \[{{x}^{2}}\]=
A)
\[2\sqrt{3}a\] done
clear
B)
\[\sqrt{3}a\] done
clear
C)
\[2\sqrt{3}{{a}^{2}}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer66)
If \[{{\cos }^{-1}}\frac{3}{5}-{{\sin }^{-1}}\frac{4}{5}={{\cos }^{-1}}x,\]then x = [AMU 1978]
A)
0 done
clear
B)
1 done
clear
C)
-1 done
clear
D)
2 done
clear
View Solution play_arrow
-
question_answer67)
\[{{\cot }^{-1}}3+\text{cose}{{\text{c}}^{-1}}\sqrt{5}\]=
A)
\[\frac{\pi }{3}\] done
clear
B)
\[\frac{\pi }{4}\] done
clear
C)
\[\frac{\pi }{6}\] done
clear
D)
\[\frac{\pi }{2}\] done
clear
View Solution play_arrow
-
question_answer68)
\[{{\tan }^{-1}}\frac{1-{{x}^{2}}}{2x}+{{\cos }^{-1}}\frac{1-{{x}^{2}}}{1+{{x}^{2}}}=\]
A)
\[\frac{\pi }{4}\] done
clear
B)
\[\frac{\pi }{2}\] done
clear
C)
\[\pi \] done
clear
D)
0 done
clear
View Solution play_arrow
-
question_answer69)
If \[{{\tan }^{-1}}(x-1)+{{\tan }^{-1}}x+{{\tan }^{-1}}(x+1)={{\tan }^{-1}}3x\],then x =
A)
\[\pm \frac{1}{2}\] done
clear
B)
\[0,\,\frac{1}{2}\] done
clear
C)
\[0,\,-\frac{1}{2}\] done
clear
D)
\[0,\,\pm \frac{1}{2}\] done
clear
View Solution play_arrow
-
question_answer70)
If \[{{\cos }^{-1}}x+{{\cos }^{-1}}y=2\pi ,\]then \[{{\sin }^{-1}}x+{{\sin }^{-1}}y\]is equal to
A)
\[\pi \] done
clear
B)
\[-\pi \] done
clear
C)
\[\frac{\pi }{2}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer71)
\[{{\sin }^{-1}}\frac{1}{\sqrt{5}}+{{\cot }^{-1}}3\]is equal to [MP PET 1993; Karnataka CET 1995]
A)
\[\frac{\pi }{6}\] done
clear
B)
\[\frac{\pi }{4}\] done
clear
C)
\[\frac{\pi }{3}\] done
clear
D)
\[\frac{\pi }{2}\] done
clear
View Solution play_arrow
-
question_answer72)
If \[{{\cot }^{-1}}\alpha +{{\cot }^{-1}}\beta ={{\cot }^{-1}}x,\]then \[x=\] [MP PET 1992]
A)
\[\alpha +\beta \] done
clear
B)
\[\alpha -\beta \] done
clear
C)
\[\frac{1+\alpha \beta }{\alpha +\beta }\] done
clear
D)
\[\frac{\alpha \beta -1}{\alpha +\beta }\] done
clear
View Solution play_arrow
-
question_answer73)
If \[{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \right)+{{\sin }^{-1}}\left( \frac{2b}{1+{{b}^{2}}} \right)=2{{\tan }^{-1}}x,\]then \[x=\] [MNR 1984; UPSEAT 1999; Pb. CET 2004]
A)
\[\frac{a-b}{1+ab}\] done
clear
B)
\[\frac{b}{1+ab}\] done
clear
C)
\[\frac{b}{1-ab}\] done
clear
D)
\[\frac{a+b}{1-ab}\] done
clear
View Solution play_arrow
-
question_answer74)
\[{{\cos }^{-1}}\frac{1}{2}+2{{\sin }^{-1}}\frac{1}{2}\]is equal to [MP PET 1998; UPSEAT 2004]
A)
\[\frac{\pi }{4}\] done
clear
B)
\[\frac{\pi }{6}\] done
clear
C)
\[\frac{\pi }{3}\] done
clear
D)
\[\frac{2\pi }{3}\] done
clear
View Solution play_arrow
-
question_answer75)
\[{{\tan }^{-1}}\frac{3}{4}+{{\tan }^{-1}}\frac{3}{5}-{{\tan }^{-1}}\frac{8}{19}=\] [AMU 1976, 77]
A)
\[\frac{\pi }{4}\] done
clear
B)
\[\frac{\pi }{3}\] done
clear
C)
\[\frac{\pi }{6}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer76)
\[4{{\tan }^{-1}}\frac{1}{5}-{{\tan }^{-1}}\frac{1}{70}+{{\tan }^{-1}}\frac{1}{99}=\] [Roorkee 1981]
A)
\[\frac{\pi }{2}\] done
clear
B)
\[\frac{\pi }{3}\] done
clear
C)
\[\frac{\pi }{4}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer77)
If \[{{\sin }^{-1}}x+{{\sin }^{-1}}y=\frac{2\pi }{3},\]then \[{{\cos }^{-1}}x+{{\cos }^{-1}}y=\] [EAMCET 1994]
A)
\[\frac{2\pi }{3}\] done
clear
B)
\[\frac{\pi }{3}\] done
clear
C)
\[\frac{\pi }{6}\] done
clear
D)
\[\pi \] done
clear
View Solution play_arrow
-
question_answer78)
\[{{\tan }^{-1}}\left( \frac{1}{4} \right)+{{\tan }^{-1}}\left( \frac{2}{9} \right)=\] [EAMCET 1994]
A)
\[\frac{1}{2}{{\cos }^{-1}}\left( \frac{3}{5} \right)\] done
clear
B)
\[\frac{1}{2}{{\sin }^{-1}}\left( \frac{3}{5} \right)\] done
clear
C)
\[\frac{1}{2}{{\tan }^{-1}}\left( \frac{3}{5} \right)\] done
clear
D)
\[{{\tan }^{-1}}\left( \frac{1}{2} \right)\] done
clear
View Solution play_arrow
-
question_answer79)
\[{{\tan }^{-1}}\left( \frac{x}{y} \right)-{{\tan }^{-1}}\,\left( \frac{x-y}{x+y} \right)\] is [EAMCET 1992]
A)
\[\frac{\pi }{2}\] done
clear
B)
\[\frac{\pi }{3}\] done
clear
C)
\[\frac{\pi }{4}\] done
clear
D)
\[\frac{\pi }{4}\]or \[-\frac{3\pi }{4}\] done
clear
View Solution play_arrow
-
question_answer80)
If \[{{\sin }^{-1}}\frac{x}{5}+\text{cose}{{\text{c}}^{-1}}\left( \frac{5}{4} \right)=\frac{\pi }{2},\]then \[x=\] [EAMCET 1983; Karnataka CET 2004]
A)
4 done
clear
B)
5 done
clear
C)
1 done
clear
D)
3 done
clear
View Solution play_arrow
-
question_answer81)
\[2{{\tan }^{-1}}\left( \frac{1}{3} \right)+{{\tan }^{-1}}\left( \frac{1}{7} \right)=\] [EAMCET 1983]
A)
\[{{\tan }^{-1}}\left( \frac{49}{29} \right)\] done
clear
B)
\[\frac{\pi }{2}\] done
clear
C)
0 done
clear
D)
\[\frac{\pi }{4}\] done
clear
View Solution play_arrow
-
question_answer82)
\[{{\cos }^{-1}}\left( \frac{15}{17} \right)+2{{\tan }^{-1}}\left( \frac{1}{5} \right)=\] [EAMCET 1981]
A)
\[\frac{\pi }{2}\] done
clear
B)
\[{{\cos }^{-1}}\left( \frac{171}{221} \right)\] done
clear
C)
\[\frac{\pi }{4}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer83)
\[{{\sin }^{-1}}\left( \frac{3}{5} \right)+{{\tan }^{-1}}\left( \frac{1}{7} \right)=\] [Karnataka CET 1994]
A)
\[\frac{\pi }{4}\] done
clear
B)
\[\frac{\pi }{2}\] done
clear
C)
\[{{\cos }^{-1}}\left( \frac{4}{5} \right)\] done
clear
D)
\[\pi \] done
clear
View Solution play_arrow
-
question_answer84)
A solution of the equation \[{{\tan }^{-1}}(1+x)\] \[+{{\tan }^{-1}}(1-x)\] \[=\frac{\pi }{2}\] is [Karnataka CET 1993]
A)
\[x=1\] done
clear
B)
\[x=-1\] done
clear
C)
\[x=0\] done
clear
D)
\[x=\pi \] done
clear
View Solution play_arrow
-
question_answer85)
If \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}={{r}^{2}}\], then\[{{\tan }^{-1}}\left( \frac{xy}{zr} \right)+\] \[{{\tan }^{-1}}\left( \frac{yz}{xr} \right)+\tan \left( \frac{zx}{yr} \right)=\]
A)
\[\pi \] done
clear
B)
\[\frac{\pi }{2}\] done
clear
C)
0 done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer86)
The greatest and the least value of \[{{({{\sin }^{-1}}x)}^{3}}+{{({{\cos }^{-1}}x)}^{3}}\]are
A)
\[-\frac{\pi }{2},\,\frac{\pi }{2}\] done
clear
B)
\[-\frac{{{\pi }^{3}}}{8},\,\frac{{{\pi }^{3}}}{8}\] done
clear
C)
\[\frac{7{{\pi }^{3}}}{8},\,\,\frac{{{\pi }^{3}}}{32}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer87)
If \[a<\frac{1}{32},\] then the number of solution of \[{{({{\sin }^{-1}}x)}^{3}}+{{({{\cos }^{-1}}x)}^{3}}=a{{\pi }^{3}}\] is
A)
0 done
clear
B)
1 done
clear
C)
2 done
clear
D)
Infinite done
clear
View Solution play_arrow
-
question_answer88)
If \[k\le {{\sin }^{-1}}x+{{\cos }^{-1}}x+{{\tan }^{-1}}x\le K,\]then
A)
\[k=0,\,K=\pi \] done
clear
B)
\[k=0,K=\frac{\pi }{2}\] done
clear
C)
\[k=\frac{\pi }{2},K=\pi \] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer89)
If \[{{({{\tan }^{-1}}x)}^{2}}+{{({{\cot }^{-1}}x)}^{2}}=\frac{5{{\pi }^{2}}}{8},\]then \[x\] equals
A)
-1 done
clear
B)
1 done
clear
C)
0 done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer90)
If \[\tan (x+y)=33\]and \[x={{\tan }^{-1}}3,\]then y will be
A)
\[0.3\] done
clear
B)
\[{{\tan }^{-1}}(1.3)\] done
clear
C)
\[{{\tan }^{-1}}(0.3)\] done
clear
D)
\[{{\tan }^{-1}}\left( \frac{1}{18} \right)\] done
clear
View Solution play_arrow
-
question_answer91)
If \[{{\tan }^{-1}}\frac{x-1}{x+1}+{{\tan }^{-1}}\frac{2x-1}{2x+1}={{\tan }^{-1}}\frac{23}{36},\]then x = [ISM Dhanbad 1973]
A)
\[\frac{3}{4},\frac{-3}{8}\] done
clear
B)
\[\frac{3}{4},\frac{3}{8}\] done
clear
C)
\[\frac{4}{3},\frac{3}{8}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer92)
\[{{\tan }^{-1}}\frac{{{c}_{1}}x-y}{{{c}_{1}}y+x}+{{\tan }^{-1}}\frac{{{c}_{2}}-{{c}_{1}}}{1+{{c}_{2}}{{c}_{1}}}+\]\[{{\tan }^{-1}}\frac{{{c}_{3}}-{{c}_{2}}}{1+{{c}_{3}}{{c}_{2}}}+...+{{\tan }^{-1}}\frac{1}{{{c}_{n}}}=\]
A)
\[{{\tan }^{-1}}\frac{y}{x}\] done
clear
B)
\[{{\tan }^{-1}}yx\] done
clear
C)
\[{{\tan }^{-1}}\frac{x}{y}\] done
clear
D)
\[{{\tan }^{-1}}(x-y)\] done
clear
View Solution play_arrow
-
question_answer93)
\[\sin \left\{ {{\sin }^{-1}}\frac{1}{2}+{{\cos }^{-1}}\frac{1}{2} \right\}=\] [EAMCET 1985]
A)
0 done
clear
B)
-1 done
clear
C)
2 done
clear
D)
1 done
clear
View Solution play_arrow
-
question_answer94)
\[{{\sin }^{-1}}\frac{4}{5}+2{{\tan }^{-1}}\frac{1}{3}=\] [ISM Dhanbad 1971]
A)
\[\frac{\pi }{2}\] done
clear
B)
\[\frac{\pi }{3}\] done
clear
C)
\[\frac{\pi }{4}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer95)
\[{{\sin }^{-1}}x+{{\cos }^{-1}}x\] is equal to [Pb. CET 1997; DCE 2002]
A)
\[\frac{\pi }{4}\] done
clear
B)
\[\frac{\pi }{2}\] done
clear
C)
-1 done
clear
D)
1 done
clear
View Solution play_arrow
-
question_answer96)
\[{{\tan }^{-1}}\frac{1}{2}+{{\tan }^{-1}}\frac{1}{3}\]= [MP PET 1997, 2003; UPSEAT 2000; Karnataka CET 2001; Pb. CET 2004]
A)
0 done
clear
B)
\[\pi /4\] done
clear
C)
\[\pi /2\] done
clear
D)
\[\pi \] done
clear
View Solution play_arrow
-
question_answer97)
\[{{\tan }^{-1}}\left( \frac{1}{11} \right)+{{\tan }^{-1}}\left( \frac{2}{12} \right)=\] [DCE 1999]
A)
\[{{\tan }^{-1}}\left( \frac{33}{132} \right)\] done
clear
B)
\[{{\tan }^{-1}}\left( \frac{1}{2} \right)\] done
clear
C)
\[{{\tan }^{-1}}\left( \frac{132}{33} \right)\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer98)
If \[{{\tan }^{-1}}x+2{{\cot }^{-1}}x=\frac{2\pi }{3},\]then x = [Karnataka CET 1999]
A)
\[\sqrt{2}\] done
clear
B)
3 done
clear
C)
\[\sqrt{3}\] done
clear
D)
\[\frac{\sqrt{3}-1}{\sqrt{3}+1}\] done
clear
View Solution play_arrow
-
question_answer99)
If \[{{\sin }^{-1}}x+{{\cot }^{-1}}\left( \frac{1}{2} \right)=\frac{\pi }{2},\]then x is [Roorkee 1999; Karnataka CET 1999]
A)
0 done
clear
B)
\[\frac{1}{\sqrt{5}}\] done
clear
C)
\[\frac{2}{\sqrt{5}}\] done
clear
D)
\[\frac{\sqrt{3}}{2}\] done
clear
View Solution play_arrow
-
question_answer100)
If \[{{\sin }^{-1}}a+{{\sin }^{-1}}b+{{\sin }^{-1}}c=\pi ,\] then the value of \[a\sqrt{(1-{{a}^{2}})}+b\sqrt{(1-{{b}^{2}})}+c\sqrt{(1-{{c}^{2}})}\] will be [UPSEAT 1999]
A)
\[2abc\] done
clear
B)
\[abc\] done
clear
C)
\[\frac{1}{2}abc\] done
clear
D)
\[\frac{1}{3}abc\] done
clear
View Solution play_arrow
-
question_answer101)
The value of \[{{\cos }^{-1}}\left( \cos \frac{5\pi }{3} \right)+{{\sin }^{-1}}\left( \sin \frac{5\pi }{3} \right)\]is [Roorkee 2000]
A)
0 done
clear
B)
\[\frac{\pi }{2}\] done
clear
C)
\[\frac{2\pi }{3}\] done
clear
D)
\[\frac{10\pi }{3}\] done
clear
View Solution play_arrow
-
question_answer102)
If \[4{{\sin }^{-1}}x+{{\cos }^{-1}}x=\pi ,\]then\[x\]is equal to [UPSEAT 2001]
A)
0 done
clear
B)
\[\frac{1}{2}\] done
clear
C)
\[-\frac{\sqrt{3}}{2}\] done
clear
D)
\[\frac{1}{\sqrt{2}}\] done
clear
View Solution play_arrow
-
question_answer103)
If \[{{\sin }^{-1}}\frac{3}{5}+{{\cos }^{-1}}\left( \frac{12}{13} \right)={{\sin }^{-1}}C,\]then C = [Pb. CET 1999]
A)
\[\frac{65}{56}\] done
clear
B)
\[\frac{24}{65}\] done
clear
C)
\[\frac{16}{65}\] done
clear
D)
\[\frac{56}{65}\] done
clear
View Solution play_arrow
-
question_answer104)
\[\sin \left\{ {{\tan }^{-1}}\left( \frac{1-{{x}^{2}}}{2x} \right)+{{\cos }^{-1}}\left( \frac{1-{{x}^{2}}}{1+{{x}^{2}}} \right) \right\}\]is equal to [Kurukshetra CEE 2001]
A)
0 done
clear
B)
1 done
clear
C)
\[\sqrt{2}\] done
clear
D)
\[\frac{1}{\sqrt{2}}\] done
clear
View Solution play_arrow
-
question_answer105)
The value of \[{{\cos }^{-1}}\left( \cos \frac{5\pi }{3} \right)+{{\sin }^{-1}}\left( \cos \frac{5\pi }{3} \right)\]is [UPSEAT 2003]
A)
\[\frac{\pi }{2}\] done
clear
B)
\[\frac{5\pi }{3}\] done
clear
C)
\[\frac{10\pi }{3}\] done
clear
D)
\[0\] done
clear
View Solution play_arrow
-
question_answer106)
The value of \[{{\sin }^{-1}}\left( \frac{\sqrt{3}}{2} \right)-{{\sin }^{-1}}\left( \frac{1}{2} \right)\]is [MP PET 2003]
A)
\[{{45}^{o}}\] done
clear
B)
\[{{90}^{o}}\] done
clear
C)
\[{{15}^{o}}\] done
clear
D)
\[{{30}^{o}}\] done
clear
View Solution play_arrow
-
question_answer107)
If \[{{\cos }^{-1}}x+{{\cos }^{-1}}y+{{\cos }^{-1}}z=3\pi ,\]then \[xy+yz+zx=\] [Karnataka CET 2003]
A)
0 done
clear
B)
1 done
clear
C)
3 done
clear
D)
-3 done
clear
View Solution play_arrow
-
question_answer108)
\[\cos \text{ }\left[ {{\cos }^{-1}}\text{ }\left( \frac{-1}{7} \right)+{{\sin }^{-1}}\text{ }\left( \frac{-1}{7} \right) \right]=\] [EAMCET 2003]
A)
\[-1/3\] done
clear
B)
0 done
clear
C)
\[1/3\] done
clear
D)
\[4/9\] done
clear
View Solution play_arrow
-
question_answer109)
The value of \[\tan \left[ {{\sin }^{-1}}\left( \frac{3}{5} \right)+{{\cos }^{-1}}\left( \frac{3}{\sqrt{13}} \right) \right]\]is [AMU 2001]
A)
\[\frac{6}{17}\] done
clear
B)
\[\frac{6}{\sqrt{13}}\] done
clear
C)
\[\frac{\sqrt{13}}{5}\] done
clear
D)
\[\frac{17}{6}\] done
clear
View Solution play_arrow
-
question_answer110)
The value of \[\tan \left( {{\tan }^{-1}}\frac{1}{2}-{{\tan }^{-1}}\frac{1}{3} \right)\]is [AMU 2001]
A)
\[5/6\] done
clear
B)
\[7/6\] done
clear
C)
\[1/6\] done
clear
D)
\[1/7\] done
clear
View Solution play_arrow
-
question_answer111)
If \[{{\cos }^{-1}}\sqrt{p}+{{\cos }^{-1}}\sqrt{1-p}+{{\cos }^{-1}}\sqrt{1-q}=\frac{3\pi }{4},\] then the value of q is [Karnataka CET 2002; Pb. CET 2000]
A)
1 done
clear
B)
\[\frac{1}{\sqrt{2}}\] done
clear
C)
\[\frac{1}{3}\] done
clear
D)
\[\frac{1}{2}\] done
clear
View Solution play_arrow
-
question_answer112)
\[{{\cot }^{-1}}[{{(\cos \alpha )}^{1/2}}]-{{\tan }^{-1}}[{{(\cos \alpha )}^{1/2}}]=x,\]then \[\sin x=\] [AIEEE 2002]
A)
\[{{\tan }^{2}}\left( \frac{\alpha }{2} \right)\] done
clear
B)
\[{{\cot }^{2}}\left( \frac{\alpha }{2} \right)\] done
clear
C)
\[\tan \alpha \] done
clear
D)
\[\cot \left( \frac{\alpha }{2} \right)\] done
clear
View Solution play_arrow
-
question_answer113)
If \[{{\tan }^{-1}}x+{{\tan }^{-1}}y+{{\tan }^{-1}}z=\pi ,\] then \[\frac{1}{xy}+\frac{1}{yz}+\frac{1}{zx}=\] [MP PET 1991]
A)
0 done
clear
B)
1 done
clear
C)
\[\frac{1}{xyz}\] done
clear
D)
\[xyz\] done
clear
View Solution play_arrow
-
question_answer114)
\[\tan \left[ \frac{1}{2}{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \right)+\frac{1}{2}{{\cos }^{-1}}\left( \frac{1-{{a}^{2}}}{1+{{a}^{2}}} \right) \right]=\]
A)
\[\frac{2a}{1+{{a}^{2}}}\] done
clear
B)
\[\frac{1-{{a}^{2}}}{1+{{a}^{2}}}\] done
clear
C)
\[\frac{2a}{1-{{a}^{2}}}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer115)
If \[A={{\tan }^{-1}}x\], then \[\sin 2A=\] [MNR 1988; UPSEAT 2000]
A)
\[\frac{2x}{\sqrt{1-{{x}^{2}}}}\] done
clear
B)
\[\frac{2x}{1-{{x}^{2}}}\] done
clear
C)
\[\frac{2x}{1+{{x}^{2}}}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer116)
If \[\cos (2{{\sin }^{-1}}x)=\frac{1}{9},\]then \[x=\] [Roorkee 1975]
A)
Only 2/3 done
clear
B)
Only -2/3 done
clear
C)
2/3, -2/3 done
clear
D)
Neither 2/3 nor -2/3 done
clear
View Solution play_arrow
-
question_answer117)
If \[2{{\tan }^{-1}}(\cos x)={{\tan }^{-1}}(2\text{cosec }x),\] then x =
A)
\[\frac{3\pi }{4}\] done
clear
B)
\[\frac{\pi }{4}\] done
clear
C)
\[\frac{\pi }{3}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer118)
\[\tan \left( 2{{\cos }^{-1}}\frac{3}{5} \right)=\]
A)
\[\frac{7}{25}\] done
clear
B)
\[\frac{24}{25}\] done
clear
C)
\[-\frac{24}{7}\] done
clear
D)
\[\frac{8}{3}\] done
clear
View Solution play_arrow
-
question_answer119)
\[\tan \left[ 2{{\tan }^{-1}}\left( \frac{1}{5} \right)-\frac{\pi }{4} \right]=\] [IIT 1984]
A)
\[\frac{17}{7}\] done
clear
B)
\[-\frac{17}{7}\] done
clear
C)
\[\frac{7}{17}\] done
clear
D)
\[-\frac{7}{17}\] done
clear
View Solution play_arrow
-
question_answer120)
If \[2{{\cos }^{-1}}\sqrt{\frac{1+x}{2}}=\frac{\pi }{2},\]then \[x=\]
A)
1 done
clear
B)
0 done
clear
C)
-1/2 done
clear
D)
1/2 done
clear
View Solution play_arrow
-
question_answer121)
\[\tan \left[ \frac{1}{2}{{\cos }^{-1}}\left( \frac{\sqrt{5}}{3} \right) \right]=\] [Roorkee 1986]
A)
\[\frac{3-\sqrt{5}}{2}\] done
clear
B)
\[\frac{3+\sqrt{5}}{2}\] done
clear
C)
\[\frac{2}{3-\sqrt{5}}\] done
clear
D)
\[\frac{2}{3+\sqrt{5}}\] done
clear
View Solution play_arrow
-
question_answer122)
\[\frac{1}{2}{{\cos }^{-1}}\left( \frac{1-x}{1+x} \right)=\]
A)
\[{{\cot }^{-1}}\sqrt{x}\] done
clear
B)
\[{{\tan }^{-1}}\sqrt{x}\] done
clear
C)
\[{{\tan }^{-1}}x\] done
clear
D)
\[{{\cot }^{-1}}x\] done
clear
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question_answer123)
\[\sin \left( 4{{\tan }^{-1}}\frac{1}{3} \right)=\]
A)
\[\frac{12}{25}\] done
clear
B)
\[\frac{24}{25}\] done
clear
C)
\[\frac{1}{5}\] done
clear
D)
None of these done
clear
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question_answer124)
\[3{{\tan }^{-1}}a\]is equal to [MP PET 1993]
A)
\[{{\tan }^{-1}}\frac{3a+{{a}^{3}}}{1+3{{a}^{2}}}\] done
clear
B)
\[{{\tan }^{-1}}\frac{3a-{{a}^{3}}}{1+3{{a}^{2}}}\] done
clear
C)
\[{{\tan }^{-1}}\frac{3a+{{a}^{3}}}{1-3{{a}^{2}}}\] done
clear
D)
\[{{\tan }^{-1}}\frac{3a-{{a}^{3}}}{1-3{{a}^{2}}}\] done
clear
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question_answer125)
\[4{{\tan }^{-1}}\frac{1}{5}-{{\tan }^{-1}}\frac{1}{239}\]is equal to [MNR 1995]
A)
\[\pi \] done
clear
B)
\[\frac{\pi }{2}\] done
clear
C)
\[\frac{\pi }{3}\] done
clear
D)
\[\frac{\pi }{4}\] done
clear
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-
question_answer126)
If \[3{{\sin }^{-1}}\frac{2x}{1-{{x}^{2}}}-4{{\cos }^{-1}}\frac{1-{{x}^{2}}}{1+{{x}^{2}}}+2{{\tan }^{-1}}\frac{2x}{1-{{x}^{2}}}=\frac{\pi }{3}\] then \[x\] =
A)
\[\sqrt{3}\] done
clear
B)
\[\frac{1}{\sqrt{3}}\] done
clear
C)
1 done
clear
D)
None of these done
clear
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question_answer127)
The value of \[\sin \left( 2{{\tan }^{-1}}\left( \frac{1}{3} \right) \right)+\cos ({{\tan }^{-1}}2\sqrt{2})=\] [AMU 1999]
A)
\[\frac{16}{15}\] done
clear
B)
\[\frac{14}{15}\] done
clear
C)
\[\frac{12}{15}\] done
clear
D)
\[\frac{11}{15}\] done
clear
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question_answer128)
\[\sin \left( \frac{1}{2}{{\cos }^{-1}}\frac{4}{5} \right)=\] [Karnataka CET 2003]
A)
\[\frac{1}{\sqrt{10}}\] done
clear
B)
\[-\frac{1}{\sqrt{10}}\] done
clear
C)
\[\frac{1}{10}\]. done
clear
D)
\[-\frac{1}{10}\] done
clear
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question_answer129)
The value of \[{{\cos }^{-1}}(\cos 12)-{{\sin }^{-1}}(\sin 14)\] is [J & K 2005]
A)
- 2 done
clear
B)
\[8\pi -26\] done
clear
C)
\[4\pi +2\] done
clear
D)
None of these done
clear
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question_answer130)
\[{{\cos }^{-1}}\left( \frac{3+5\cos x}{5+3\cos x} \right)\] is equal to [Kerala (Engg.) 2005]
A)
\[{{\tan }^{-1}}\left( \frac{1}{2}\tan \frac{x}{2} \right)\] done
clear
B)
\[2{{\tan }^{-1}}\left( 2\tan \frac{x}{2} \right)\] done
clear
C)
\[\frac{1}{2}{{\tan }^{-1}}\left( 2\tan \frac{x}{2} \right)\] done
clear
D)
\[2{{\tan }^{-1}}\left( \frac{1}{2}\tan \frac{x}{2} \right)\] done
clear
E)
\[{{\tan }^{-1}}\left( \tan \frac{x}{2} \right)\] done
clear
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question_answer131)
If \[{{\cos }^{-1}}x-{{\cos }^{-1}}\frac{y}{2}=\alpha \], then \[4{{x}^{2}}-4xy\cos \alpha +{{y}^{2}}\] is equal to [AIEEE 2005]
A)
\[4{{\sin }^{2}}\alpha \] done
clear
B)
\[-4{{\sin }^{2}}\alpha \] done
clear
C)
\[2\sin 2\alpha \] done
clear
D)
\[4\] done
clear
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-
question_answer132)
If \[{{\tan }^{-1}}x+{{\tan }^{-1}}y=\frac{\pi }{4}\] then [Karnataka CET 2005]
A)
\[x+y+xy=1\] done
clear
B)
\[x+y-xy=1\] done
clear
C)
\[x+y+xy+1=0\] done
clear
D)
\[x+y-xy+1=0\] done
clear
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question_answer133)
If \[{{\sin }^{-1}}(1-x)-2{{\sin }^{-1}}x=\pi /2\], then x equals [Orissa JEE 2005]
A)
\[\left( 0,\,-\frac{1}{2} \right)\] done
clear
B)
\[\left( \frac{1}{2},\,0 \right)\] done
clear
C)
{0} done
clear
D)
(-1, 0) done
clear
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-
question_answer134)
If \[\angle A={{90}^{o}}\] in the triangle ABC, then \[{{\tan }^{-1}}\left( \frac{c}{a+b} \right)+{{\tan }^{-1}}\left( \frac{b}{a+c} \right)=\] [Kerala (Engg.) 2005]
A)
0 done
clear
B)
1 done
clear
C)
\[\pi /4\] done
clear
D)
\[\pi /6\] done
clear
E)
\[\pi /8\] done
clear
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question_answer135)
The solution of \[{{\sin }^{-1}}x-{{\sin }^{-1}}2x=\pm \frac{\pi }{3}\] is [Karnataka CET 2005]
A)
\[\pm \frac{1}{3}\] done
clear
B)
\[\pm \frac{1}{4}\] done
clear
C)
\[\pm \frac{\sqrt{3}}{2}\] done
clear
D)
\[\pm \frac{1}{2}\] done
clear
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question_answer136)
For the equation \[{{\cos }^{-1}}x+{{\cos }^{-1}}2x+\pi =0\], the number of real solution is [Orissa JEE 2005]
A)
1 done
clear
B)
2 done
clear
C)
0 done
clear
D)
\[\infty \] done
clear
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question_answer137)
\[\sin \text{ }\left[ 3\,{{\sin }^{-1}}\left( \frac{1}{5} \right) \right]=\] [Kerala (Engg.) 2005]
A)
71/125 done
clear
B)
74/125 done
clear
C)
3/5 done
clear
D)
1/2 done
clear
E)
- 3/5 done
clear
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