-
question_answer1)
\[\int_{{}}^{{}}{\frac{dx}{1+{{e}^{x}}}=}\] [MP PET 1991; Roorkee 1977]
A)
\[\log (1+{{e}^{x}})\] done
clear
B)
\[-\log (1+{{e}^{-x}})\] done
clear
C)
\[-\log (1-{{e}^{-x}})\] done
clear
D)
\[\log ({{e}^{-x}}+{{e}^{-2x}})\] done
clear
View Solution play_arrow
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question_answer2)
\[\int_{{}}^{{}}{\frac{dx}{{{e}^{x}}+{{e}^{-x}}}=}\] [Bihar CEE 1976; MNR 1974]
A)
\[{{\tan }^{-1}}({{e}^{-x}})\] done
clear
B)
\[{{\tan }^{-1}}({{e}^{x}})\] done
clear
C)
\[\log ({{e}^{x}}-{{e}^{-x}})\] done
clear
D)
\[\log ({{e}^{x}}+{{e}^{-x}})\] done
clear
View Solution play_arrow
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question_answer3)
\[\int_{{}}^{{}}{\frac{{{e}^{\sqrt{x}}}\cos {{e}^{\sqrt{x}}}}{\sqrt{x}}dx}=\]
A)
\[2\sin {{e}^{\sqrt{x}}}\] done
clear
B)
\[\sin {{e}^{\sqrt{x}}}\] done
clear
C)
\[2\cos {{e}^{\sqrt{x}}}\] done
clear
D)
\[-2\sin {{e}^{\sqrt{x}}}\] done
clear
View Solution play_arrow
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question_answer4)
\[\int_{{}}^{{}}{\frac{dx}{x+x\log x}=}\] [MP PET 1993; Roorkee 1977]
A)
\[\log (1+\log x)\] done
clear
B)
\[\log \log (1+\log x)\] done
clear
C)
\[\log x+\log (\log x)\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer5)
To find the value of \[\int_{{}}^{{}}{\frac{1+\log x}{x}\text{ }}dx\], the proper substitution is [MP PET 1988]
A)
\[\log x=t\] done
clear
B)
\[1+\log x=t\] done
clear
C)
\[\frac{1}{x}=t\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer6)
\[\int_{{}}^{{}}{\frac{\sec x\ dx}{\sqrt{\cos 2x}}}=\]
A)
\[{{\sin }^{-1}}(\tan x)\] done
clear
B)
\[\tan x\] done
clear
C)
\[{{\cos }^{-1}}(\tan x)\] done
clear
D)
\[\frac{\sin x}{\sqrt{\cos x}}\] done
clear
View Solution play_arrow
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question_answer7)
To find the value of \[\int_{{}}^{{}}{\frac{dx}{x\sqrt{2ax-{{x}^{2}}}}}\], the suitable substitution is
A)
\[x=a\cos t\] done
clear
B)
\[x=2a\cos t\] done
clear
C)
\[x=2at\] done
clear
D)
\[x=2a{{\sin }^{2}}t\] done
clear
View Solution play_arrow
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question_answer8)
\[\int_{{}}^{{}}{\frac{x\ dx}{1-x\cot x}}=\]
A)
\[\log (\cos x-x\sin x)+c\] done
clear
B)
\[\log (x\sin x-\cos x)+c\] done
clear
C)
\[\log (\sin x-x\cos x)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer9)
\[\int_{{}}^{{}}{\frac{\sin 2x}{1+{{\sin }^{2}}x}dx=}\] [Roorkee 1976]
A)
\[\log \sin 2x+c\] done
clear
B)
\[\log (1+{{\sin }^{2}}x)+c\] done
clear
C)
\[\frac{1}{2}\log (1+{{\sin }^{2}}x)+c\] done
clear
D)
\[{{\tan }^{-1}}(\sin x)+c\] done
clear
View Solution play_arrow
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question_answer10)
\[\int_{{}}^{{}}{\frac{{{x}^{3}}}{\sqrt{{{x}^{2}}+2}}dx=}\]
A)
\[\frac{1}{3}{{({{x}^{2}}+2)}^{3/2}}+2{{({{x}^{2}}+2)}^{1/2}}+c\] done
clear
B)
\[\frac{1}{3}{{({{x}^{2}}+2)}^{3/2}}-2{{({{x}^{2}}+2)}^{1/2}}+c\] done
clear
C)
\[\frac{1}{3}{{({{x}^{2}}+2)}^{3/2}}+{{({{x}^{2}}+2)}^{1/2}}+c\] done
clear
D)
\[\frac{1}{3}{{({{x}^{2}}+2)}^{3/2}}-{{({{x}^{2}}+2)}^{1/2}}+c\] done
clear
View Solution play_arrow
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question_answer11)
\[\int_{{}}^{{}}{\frac{{{x}^{e-1}}+{{e}^{x-1}}}{{{x}^{e}}+{{e}^{x}}}dx=}\]
A)
\[\log ({{x}^{e}}+{{e}^{x}})+c\] done
clear
B)
\[e\log ({{x}^{e}}+{{e}^{x}})+c\] done
clear
C)
\[\frac{1}{e}\log ({{x}^{e}}+{{e}^{x}})+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer12)
\[\int_{{}}^{{}}{\frac{\sin x\ dx}{{{a}^{2}}+{{b}^{2}}{{\cos }^{2}}x}}=\]
A)
\[\log ({{a}^{2}}+{{b}^{2}}{{\cos }^{2}}x)+c\] done
clear
B)
\[\frac{1}{ab}{{\tan }^{-1}}\left( \frac{a\cos x}{b} \right)+c\] done
clear
C)
\[\frac{1}{ab}{{\cot }^{-1}}\left( \frac{b\cos x}{a} \right)+c\] done
clear
D)
\[\frac{1}{ab}{{\cot }^{-1}}\left( \frac{a\cos x}{b} \right)+c\] done
clear
View Solution play_arrow
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question_answer13)
\[\int_{{}}^{{}}{\sec x\log (\sec x+\tan x)\ dx=}\]
A)
\[{{[\log (\sec x+\tan x)]}^{2}}+c\] done
clear
B)
\[\frac{1}{2}{{[\log (\sec x+\tan x)]}^{2}}+c\] done
clear
C)
\[{{\sec }^{2}}x+\tan x\sec x+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer14)
\[\int_{{}}^{{}}{\frac{x-2}{{{x}^{2}}-4x+3}dx=}\] [MP PET 1987]
A)
\[\log \sqrt{{{x}^{2}}-4x+3}+c\] done
clear
B)
\[x\log (x-3)-2\log (x-2)+c\] done
clear
C)
\[\log [(x-3)(x-1)]\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer15)
\[\int_{{}}^{{}}{\frac{3{{x}^{2}}}{{{x}^{6}}+1}dx=}\] [MNR 1981; MP PET 1988; RPET 1995]
A)
\[\log ({{x}^{6}}+1)+c\] done
clear
B)
\[{{\tan }^{-1}}({{x}^{3}})+c\] done
clear
C)
\[3{{\tan }^{-1}}({{x}^{3}})+c\] done
clear
D)
\[3{{\tan }^{-1}}\left( \frac{{{x}^{3}}}{3} \right)+c\] done
clear
View Solution play_arrow
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question_answer16)
\[\int_{{}}^{{}}{\frac{\cot x}{\log \sin x}}\ dx=\] [MNR 1974]
A)
\[\log (\log \sin x)+c\] done
clear
B)
\[\log (\log \text{cosec}\,x)+c\] done
clear
C)
\[2\log (\log \sin x)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer17)
\[\int_{{}}^{{}}{\frac{{{(1+\log x)}^{2}}}{x}}\ dx=\] [Roorkee 1977]
A)
\[{{(1+\log x)}^{3}}+c\] done
clear
B)
\[3{{(1+\log x)}^{3}}+c\] done
clear
C)
\[\frac{1}{3}{{(1+\log x)}^{3}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer18)
\[\int_{{}}^{{}}{{{\sec }^{p}}x\tan x\ dx=}\]
A)
\[\frac{{{\sec }^{p+1}}x}{p+1}+c\] done
clear
B)
\[\frac{{{\sec }^{p}}x}{p}+c\] done
clear
C)
\[\frac{{{\tan }^{p+1}}x}{p+1}+c\] done
clear
D)
\[\frac{{{\tan }^{p}}x}{p}+c\] done
clear
View Solution play_arrow
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question_answer19)
\[\int_{{}}^{{}}{\frac{dx}{{{e}^{x}}-1}=}\] [MP PET 1989]
A)
\[\ln (1-{{e}^{-x}})+c\] done
clear
B)
\[-\ln (1-{{e}^{-x}})+c\] done
clear
C)
\[\ln ({{e}^{x}}-1)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer20)
\[\int_{{}}^{{}}{{{x}^{2}}\sec {{x}^{3}}\ dx}=\] [MNR 1986; Roorkee 1975]
A)
\[\log (\sec {{x}^{3}}+\tan {{x}^{3}})\] done
clear
B)
\[3(\sec {{x}^{3}}+\tan {{x}^{3}})\] done
clear
C)
\[\frac{1}{3}\log (\sec {{x}^{3}}+\tan {{x}^{3}})\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer21)
\[\int_{{}}^{{}}{\frac{\sin 2x}{{{\sin }^{4}}x+{{\cos }^{4}}x}dx=}\] [RPET 1995]
A)
\[{{\cot }^{-1}}({{\tan }^{2}}x)+c\] done
clear
B)
\[{{\tan }^{-1}}({{\tan }^{2}}x)+c\] done
clear
C)
\[{{\cot }^{-1}}({{\cot }^{2}}x)+c\] done
clear
D)
\[{{\tan }^{-1}}({{\cot }^{2}}x)+c\] done
clear
View Solution play_arrow
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question_answer22)
\[\int_{{}}^{{}}{\frac{x-2}{x(2\log x-x)}dx}=\]
A)
\[\log (2\log x-x)+c\] done
clear
B)
\[\log \left( \frac{1}{2\log x-x} \right)+c\] done
clear
C)
\[\log (x-2\log x)+c\] done
clear
D)
\[\log \left( \frac{1}{x-2\log x} \right)+c\] done
clear
View Solution play_arrow
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question_answer23)
\[\int_{{}}^{{}}{x\sqrt{1+{{x}^{2}}}}\ dx=\] [MP PET 1989]
A)
\[\frac{1+2{{x}^{2}}}{\sqrt{1+{{x}^{2}}}}+c\] done
clear
B)
\[\sqrt{1+{{x}^{2}}}+c\] done
clear
C)
\[3{{(1+{{x}^{2}})}^{3/2}}+c\] done
clear
D)
\[\frac{1}{3}{{(1+{{x}^{2}})}^{3/2}}+c\] done
clear
View Solution play_arrow
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question_answer24)
\[\int_{{}}^{{}}{\frac{{{e}^{x}}(x+1)}{{{\cos }^{2}}(x{{e}^{x}})}dx=}\] [Roorkee 1979; MP PET 1995; Pb. CET 2001]
A)
\[\tan (x{{e}^{x}})+c\] done
clear
B)
\[\sec (x{{e}^{x}})\tan (x{{e}^{x}})+c\] done
clear
C)
\[-\tan (x{{e}^{x}})+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer25)
\[\int_{{}}^{{}}{\frac{\cos \sqrt{x}}{\sqrt{x}}}dx=\] [MP PET 1987; IIT 1990; SCRA 1996; RPET 2001]
A)
\[2\cos \sqrt{x}+c\] done
clear
B)
\[2\sin \sqrt{x}+c\] done
clear
C)
\[\sin \sqrt{x}+c\] done
clear
D)
\[\frac{1}{2}\cos \sqrt{x}+c\] done
clear
View Solution play_arrow
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question_answer26)
\[\int_{{}}^{{}}{\frac{x+1}{\sqrt{1+{{x}^{2}}}}dx}=\] [MP PET 1991]
A)
\[\sqrt{1+{{x}^{2}}}+{{\tan }^{-1}}x+c\] done
clear
B)
\[\sqrt{1+{{x}^{2}}}-\log \{x+\sqrt{1+{{x}^{2}}}\}+c\] done
clear
C)
\[\sqrt{1+{{x}^{2}}}+\log \{x+\sqrt{1+{{x}^{2}}}\}+c\] done
clear
D)
\[\sqrt{1+{{x}^{2}}}+\log (\sec x+\tan x)+c\] done
clear
View Solution play_arrow
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question_answer27)
\[\int_{{}}^{{}}{\frac{\sin x\cos x}{a{{\cos }^{2}}x+b{{\sin }^{2}}x}dx=}\] [AI CBSE 1988, 89]
A)
\[\frac{1}{2(b-a)}\log (a{{\cos }^{2}}x+b{{\sin }^{2}}x)+c\] done
clear
B)
\[\frac{1}{b-a}\log (a{{\cos }^{2}}x+b{{\sin }^{2}}x)+c\] done
clear
C)
\[\frac{1}{2}\log (a{{\cos }^{2}}x+b{{\sin }^{2}}x)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer28)
\[\int_{{}}^{{}}{\frac{{{e}^{{{\tan }^{-1}}x}}}{1+{{x}^{2}}}dx=}\] [MP PET 1987]
A)
\[\log (1+{{x}^{2}})+c\] done
clear
B)
\[\log {{e}^{{{\tan }^{-1}}x}}+c\] done
clear
C)
\[{{e}^{{{\tan }^{-1}}x}}+c\] done
clear
D)
\[{{\tan }^{-1}}{{e}^{{{\tan }^{-1}}x}}+c\] done
clear
View Solution play_arrow
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question_answer29)
\[\int_{{}}^{{}}{\frac{1}{x{{(\log x)}^{2}}}}\ dx=\]
A)
\[\frac{1}{\log x}+c\] done
clear
B)
\[-\frac{1}{\log x}+c\] done
clear
C)
\[\log \log x+c\] done
clear
D)
\[-\log \log x+c\] done
clear
View Solution play_arrow
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question_answer30)
\[\int_{{}}^{{}}{\frac{1}{\sqrt{x}}{{\tan }^{4}}\sqrt{x}}{{\sec }^{2}}\sqrt{x}\ dx=\]
A)
\[2{{\tan }^{5}}\sqrt{x}+c\] done
clear
B)
\[\frac{1}{5}{{\tan }^{5}}\sqrt{x}+c\] done
clear
C)
\[\frac{2}{5}{{\tan }^{5}}\sqrt{x}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer31)
\[\int_{{}}^{{}}{\frac{{{a}^{x}}}{\sqrt{1-{{a}^{2x}}}}dx=}\] [MNR 1983, 87]
A)
\[\frac{1}{\log a}{{\sin }^{-1}}{{a}^{x}}+c\] done
clear
B)
\[{{\sin }^{-1}}{{a}^{x}}+c\] done
clear
C)
\[\frac{1}{\log a}{{\cos }^{-1}}{{a}^{x}}+c\] done
clear
D)
\[{{\cos }^{-1}}{{a}^{x}}+c\] done
clear
View Solution play_arrow
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question_answer32)
\[\int_{{}}^{{}}{\frac{\sqrt{\tan x}}{\sin x\cos x}}\ dx=\] [Bihar CEE 1974; MP PET 2002; Kerala (Engg.) 2002]
A)
\[2\sqrt{\sec x}+c\] done
clear
B)
\[2\sqrt{\tan x}+c\] done
clear
C)
\[\frac{2}{\sqrt{\tan x}}+c\] done
clear
D)
\[\frac{2}{\sqrt{\sec x}}+c\] done
clear
View Solution play_arrow
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question_answer33)
\[\int_{{}}^{{}}{\frac{\sin 2x}{{{a}^{2}}+{{b}^{2}}{{\sin }^{2}}x}}\ dx=\] [Roorkee 1977]
A)
\[\frac{1}{{{b}^{2}}}\log ({{a}^{2}}+{{b}^{2}}{{\sin }^{2}}x)+c\] done
clear
B)
\[\frac{1}{b}\log ({{a}^{2}}+{{b}^{2}}{{\sin }^{2}}x)+c\] done
clear
C)
\[\log ({{a}^{2}}+{{b}^{2}}{{\sin }^{2}}x)+c\] done
clear
D)
\[{{b}^{2}}\log ({{a}^{2}}+{{b}^{2}}{{\sin }^{2}}x)+c\] done
clear
View Solution play_arrow
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question_answer34)
\[\int_{{}}^{{}}{\frac{1}{x\sqrt{1+\log x}}\ dx=}\] [Roorkee 1977]
A)
\[\frac{2}{3}{{(1+\log x)}^{3/2}}+c\] done
clear
B)
\[{{(1+\log x)}^{3/2}}+c\] done
clear
C)
\[2\sqrt{1+\log x}+c\] done
clear
D)
\[\sqrt{1+\log x}+c\] done
clear
View Solution play_arrow
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question_answer35)
\[\int_{{}}^{{}}{\frac{{{\sec }^{2}}x}{1+\tan x}\ dx=}\] [MP PET 1987]
A)
\[\log (\cos x+\sin x)+c\] done
clear
B)
\[\log ({{\sec }^{2}}x)+c\] done
clear
C)
\[\log (1+\tan x)+c\] done
clear
D)
\[-\frac{1}{{{(1+\tan x)}^{2}}}+c\] done
clear
View Solution play_arrow
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question_answer36)
\[\int_{{}}^{{}}{\frac{{{e}^{2x}}-1}{{{e}^{2x}}+1}}\ dx=\] [MP PET 1987]
A)
\[\frac{{{e}^{2x}}-1}{{{e}^{2x}}+1}+c\] done
clear
B)
\[\log ({{e}^{2x}}+1)-x+c\] done
clear
C)
\[\log ({{e}^{2x}}+1)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer37)
\[\int_{{}}^{{}}{\frac{\cos \text{ec}x}{\log \tan \frac{x}{2}}\ dx=}\]
A)
\[\log \left( \log \tan \frac{x}{2} \right)+c\] done
clear
B)
\[2\log \left( \log \tan \frac{x}{2} \right)+c\] done
clear
C)
\[\frac{1}{2}\log \left( \log \tan \frac{x}{2} \right)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer38)
\[\int_{{}}^{{}}{\frac{1}{{{\cos }^{2}}x{{(1-\tan x)}^{2}}}dx=}\]
A)
\[\frac{1}{\tan x-1}+c\] done
clear
B)
\[\frac{1}{1-\tan x}+c\] done
clear
C)
\[-\frac{1}{3}\frac{1}{{{(1-\tan x)}^{3}}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer39)
\[\int_{{}}^{{}}{\frac{10{{x}^{9}}+{{10}^{x}}{{\log }_{e}}10}{{{10}^{x}}+{{x}^{10}}}}\ dx=\] [MNR 1979]
A)
\[-\frac{1}{2}\frac{1}{{{({{10}^{x}}+{{x}^{10}})}^{2}}}+c\] done
clear
B)
\[\log ({{10}^{x}}+{{x}^{10}})+c\] done
clear
C)
\[\frac{1}{2}\frac{1}{{{({{10}^{x}}+{{x}^{10}})}^{2}}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer40)
\[\int_{{}}^{{}}{\frac{1}{{{({{e}^{x}}+{{e}^{-x}})}^{2}}}\ dx=}\]
A)
\[-\frac{1}{2({{e}^{2x}}+1)}+c\] done
clear
B)
\[\frac{1}{2({{e}^{2x}}+1)}+c\] done
clear
C)
\[-\frac{1}{{{e}^{2x}}+1}\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer41)
\[\int_{{}}^{{}}{\frac{\cos 2x}{{{(\cos x+\sin x)}^{2}}}\ dx=}\]
A)
\[\log \sqrt{\cos x+\sin x}+c\] done
clear
B)
\[\log (\cos x-\sin x)+c\] done
clear
C)
\[\log (\cos x+\sin x)+c\] done
clear
D)
\[-\frac{1}{\cos x+\sin x}+c\] done
clear
View Solution play_arrow
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question_answer42)
\[\int_{{}}^{{}}{\frac{\tan (\log x)}{x}\ dx=}\]
A)
\[\log \cos (\log x)+c\] done
clear
B)
\[\log \sin (\log x)+c\] done
clear
C)
\[\log \sec (\log x)+c\] done
clear
D)
\[\log \text{cosec}(\log x)+c\] done
clear
View Solution play_arrow
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question_answer43)
\[\int_{{}}^{{}}{{{\cos }^{3}}x\ {{e}^{\log (\sin x)}}}\ dx\] is equal to
A)
\[-\frac{{{\sin }^{4}}x}{4}+c\] done
clear
B)
\[-\frac{{{\cos }^{4}}x}{4}+c\] done
clear
C)
\[\frac{{{e}^{\sin x}}}{4}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer44)
\[\int_{{}}^{{}}{\tan (3x-5)\sec (3x-5)\ dx=}\] [MP PET 1988]
A)
\[\sec (3x-5)+c\] done
clear
B)
\[\frac{1}{3}\sec (3x-5)+c\] done
clear
C)
\[\tan (3x-5)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer45)
\[\int_{{}}^{{}}{\frac{x}{1+{{x}^{4}}}\ dx=}\] [IIT 1978; UPSEAT 2002]
A)
\[\frac{1}{2}{{\cot }^{-1}}{{x}^{2}}+c\] done
clear
B)
\[\frac{1}{2}{{\tan }^{-1}}{{x}^{2}}+c\] done
clear
C)
\[{{\cot }^{-1}}{{x}^{2}}+c\] done
clear
D)
\[{{\tan }^{-1}}{{x}^{2}}+c\] done
clear
View Solution play_arrow
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question_answer46)
\[\int_{{}}^{{}}{\frac{{{e}^{-x}}}{1+{{e}^{x}}}\ dx=}\]
A)
\[\log (1+{{e}^{x}})-x-{{e}^{-x}}+c\] done
clear
B)
\[\log (1+{{e}^{x}})+x-{{e}^{-x}}+c\] done
clear
C)
\[\log (1+{{e}^{x}})-x+{{e}^{-x}}+c\] done
clear
D)
\[\log (1+{{e}^{x}})+x+{{e}^{-x}}+c\] done
clear
View Solution play_arrow
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question_answer47)
\[\int_{{}}^{{}}{\frac{1}{\sqrt{1-{{e}^{2x}}}}\ dx=}\] [MP PET 1993, 2002; RPET 1999]
A)
\[x-\log [1+\sqrt{1-{{e}^{2x}}}]+c\] done
clear
B)
\[x+\log [1+\sqrt{1-{{e}^{2x}}}]+c\] done
clear
C)
\[\log [1+\sqrt{1-{{e}^{2x}}}]-x+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer48)
\[\int_{{}}^{{}}{\frac{3{{x}^{2}}}{\sqrt{9-16{{x}^{6}}}}}\ dx=\]
A)
\[\frac{1}{4}{{\sin }^{-1}}\left( \frac{4{{x}^{3}}}{3} \right)+c\] done
clear
B)
\[\frac{1}{3}{{\sin }^{-1}}\left( \frac{4{{x}^{3}}}{3} \right)+c\] done
clear
C)
\[\frac{1}{4}{{\sin }^{-1}}{{x}^{3}}+c\] done
clear
D)
\[\frac{1}{3}{{\sin }^{-1}}{{x}^{3}}+c\] done
clear
View Solution play_arrow
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question_answer49)
\[\int_{{}}^{{}}{\cos x\sqrt{4-{{\sin }^{2}}x}}\ dx=\]
A)
\[\frac{1}{2}\sin x\sqrt{4-{{\sin }^{2}}x}-2{{\sin }^{-1}}\left( \frac{1}{2}\sin x \right)+c\] done
clear
B)
\[\frac{1}{2}\sin x\sqrt{4-{{\sin }^{2}}x}+2{{\sin }^{-1}}\left( \frac{1}{2}\sin x \right)+c\] done
clear
C)
\[\frac{1}{2}\sin x\sqrt{4-{{\sin }^{2}}x}+{{\sin }^{-1}}\left( \frac{1}{2}\sin x \right)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer50)
\[\int_{{}}^{{}}{{{x}^{2}}{{(3)}^{{{x}^{3}}+1}}dx=}\]
A)
\[{{(3)}^{{{x}^{3}}}}+c\] done
clear
B)
\[\frac{{{(3)}^{{{x}^{3}}}}}{\log 3}+c\] done
clear
C)
\[\log 3{{(3)}^{{{x}^{3}}}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer51)
\[\int_{{}}^{{}}{{{\sec }^{2/3}}x\,\text{cose}{{\text{c}}^{4/3}}x\ dx=}\]
A)
\[-3{{(\tan x)}^{1/3}}+c\] done
clear
B)
\[-3{{(\tan x)}^{-1/3}}+c\] done
clear
C)
\[3{{(\tan x)}^{-1/3}}+c\] done
clear
D)
\[{{(\tan x)}^{-1/3}}+c\] done
clear
View Solution play_arrow
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question_answer52)
\[\int_{{}}^{{}}{{{\cos }^{5}}x\ dx=}\]
A)
\[\sin x-\frac{2}{3}{{\sin }^{3}}x+\frac{1}{5}{{\sin }^{5}}x+c\] done
clear
B)
\[\sin x+\frac{2}{3}{{\sin }^{3}}x+\frac{1}{5}{{\sin }^{5}}x+c\] done
clear
C)
\[\sin x-\frac{2}{3}{{\sin }^{3}}x-\frac{1}{5}{{\sin }^{5}}x+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer53)
\[\int_{{}}^{{}}{\sec x{{\tan }^{3}}x\ dx=}\]
A)
\[\frac{1}{3}{{\sec }^{3}}x-\sec x+c\] done
clear
B)
\[{{\sec }^{3}}x-\sec x+c\] done
clear
C)
\[\frac{1}{3}{{\sec }^{3}}x+\sec x+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer54)
\[\int_{{}}^{{}}{\frac{d\theta }{\sin \theta {{\cos }^{3}}\theta }=}\]
A)
\[\log \tan \theta +{{\tan }^{2}}\theta +c\] done
clear
B)
\[\log \tan \theta -\frac{1}{2}{{\tan }^{2}}\theta +c\] done
clear
C)
\[\log \tan \theta +\frac{1}{2}{{\tan }^{2}}\theta +c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer55)
\[\int_{{}}^{{}}{\frac{1}{{{\cos }^{-1}}x.\sqrt{1-{{x}^{2}}}}dx=}\]
A)
\[\log ({{\cos }^{-1}}x)+c\] done
clear
B)
\[-\log ({{\cos }^{-1}}x)+c\] done
clear
C)
\[-\frac{1}{2{{({{\cos }^{-1}}x)}^{2}}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer56)
To evaluate \[\int_{{}}^{{}}{{{x}^{3}}{{e}^{3{{x}^{2}}+5}}}dx\], the simplest way is to
A)
Substitute \[{{x}^{2}}=t\] done
clear
B)
Substitute \[(3{{x}^{2}}+5)=t\] done
clear
C)
Integrate by parts done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer57)
To evaluate \[\int_{{}}^{{}}{\frac{{{\sec }^{2}}x}{(1+\tan x)(2+\tan x)}\ dx}\], the most suitable substitution is
A)
\[1+\tan x=t\] done
clear
B)
\[2+\tan x=t\] done
clear
C)
\[\tan x=t\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer58)
\[\int_{{}}^{{}}{\frac{\text{cose}{{\text{c}}^{2}}x}{1+\cot x}dx=}\] [MNR 1973]
A)
\[\log (1+\cot x)+c\] done
clear
B)
\[-\log (1+\cot x)+c\] done
clear
C)
\[\frac{1}{2{{(1+\cot x)}^{2}}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer59)
\[\int_{{}}^{{}}{\frac{1}{\sqrt{x}}}\sin \sqrt{x}\ dx=\] [MP PET 1989]
A)
\[-\frac{1}{2}\cos \sqrt{x}+c\] done
clear
B)
\[-2\cos \sqrt{x}+c\] done
clear
C)
\[\frac{1}{2}\cos \sqrt{x}+c\] done
clear
D)
\[2\cos \sqrt{x}+c\] done
clear
View Solution play_arrow
-
question_answer60)
\[\int_{{}}^{{}}{{{e}^{x}}{{\tan }^{2}}({{e}^{x}})dx=}\]
A)
\[\tan ({{e}^{x}})-x+c\] done
clear
B)
\[{{e}^{x}}(\tan {{e}^{x}}-1)+c\] done
clear
C)
\[\sec ({{e}^{x}})+c\] done
clear
D)
\[\tan ({{e}^{x}})-{{e}^{x}}+c\] done
clear
View Solution play_arrow
-
question_answer61)
\[\int_{{}}^{{}}{\frac{dx}{{{e}^{-2x}}{{({{e}^{2x}}+1)}^{2}}}=}\]
A)
\[\frac{-1}{2({{e}^{2x}}+1)}+c\] done
clear
B)
\[\frac{1}{2({{e}^{2x}}+1)}+c\] done
clear
C)
\[\frac{1}{{{e}^{2x}}+1}+c\] done
clear
D)
\[\frac{-1}{{{e}^{2x}}+1}+c\] done
clear
View Solution play_arrow
-
question_answer62)
. \[\int_{{}}^{{}}{{{\tan }^{4}}x\ dx=}\]
A)
\[{{\tan }^{3}}x-\tan x+x+c\] done
clear
B)
\[\frac{1}{3}{{\tan }^{3}}x-\tan x+x+c\] done
clear
C)
\[\frac{1}{3}{{\tan }^{3}}x+\tan x+x+c\] done
clear
D)
\[\frac{1}{3}{{\tan }^{3}}x+\tan x+2x+c\] done
clear
View Solution play_arrow
-
question_answer63)
\[\int_{{}}^{{}}{\frac{dx}{x\sqrt{1-{{(\log x)}^{2}}}}=}\]
A)
\[{{\cos }^{-1}}(\log x)+c\] done
clear
B)
\[x\log (1-{{x}^{2}})+c\] done
clear
C)
\[{{\sin }^{-1}}(\log x)+c\] done
clear
D)
\[\frac{1}{2}{{\cos }^{-1}}(\log x)+c\] done
clear
View Solution play_arrow
-
question_answer64)
\[\int_{{}}^{{}}{\frac{f'(x)}{{{[f(x)]}^{2}}}}\ dx=\]
A)
\[-{{[f(x)]}^{-1}}+c\] done
clear
B)
\[\log [f(x)]+c\] done
clear
C)
\[{{e}^{f(x)}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer65)
For which of the following functions, the substitution \[{{x}^{2}}=t\]is applicable
A)
\[\int_{{}}^{{}}{{{x}^{6}}{{\tan }^{-1}}{{x}^{3}}}\ dx\] done
clear
B)
\[\int_{{}}^{{}}{{{\tan }^{-1}}\left( \frac{2x}{1-{{x}^{2}}} \right)\ dx}\] done
clear
C)
\[\int_{{}}^{{}}{{{x}^{3}}\cos {{x}^{2}}\ dx}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer66)
\[\int_{{}}^{{}}{\tan x}{{\sec }^{2}}x\sqrt{1-{{\tan }^{2}}x}\ dx=\]
A)
\[-\frac{1}{3}{{(1-{{\tan }^{2}}x)}^{3/2}}+c\] done
clear
B)
\[\frac{1}{3}{{(1-{{\tan }^{2}}x)}^{3/2}}+c\] done
clear
C)
\[-\frac{2}{3}{{(1-{{\tan }^{2}}x)}^{2/3}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer67)
\[\int_{{}}^{{}}{\frac{\sin 2x}{\sin 5x\sin 3x}}\ dx=\]
A)
\[\log \sin 3x-\log \sin 5x+c\] done
clear
B)
\[\frac{1}{3}\log \sin 3x+\frac{1}{5}\log \sin 5x+c\] done
clear
C)
\[\frac{1}{3}\log \sin 3x-\frac{1}{5}\log \sin 5x+c\] done
clear
D)
\[3\log \sin 3x-5\log \sin 5x+c\] done
clear
View Solution play_arrow
-
question_answer68)
\[\int_{{}}^{{}}{\frac{{{e}^{x}}\ dx}{\sqrt{1-{{e}^{2x}}}}=}\]
A)
\[{{\cos }^{-1}}({{e}^{x}})+c\] done
clear
B)
\[-{{\cos }^{-1}}({{e}^{x}})+c\] done
clear
C)
\[{{\cos }^{-1}}({{e}^{2x}})+c\] done
clear
D)
\[\sqrt{1-{{e}^{2x}}}+c\] done
clear
View Solution play_arrow
-
question_answer69)
\[\int_{{}}^{{}}{\frac{1}{\log a}({{a}^{x}}\cos {{a}^{x}})dx=}\]
A)
\[\sin {{a}^{x}}+c\] done
clear
B)
\[{{a}^{x}}\sin {{a}^{x}}+c\] done
clear
C)
\[\frac{1}{{{(\log a)}^{2}}}\sin {{a}^{x}}+c\] done
clear
D)
\[\log \sin {{a}^{x}}+c\] done
clear
View Solution play_arrow
-
question_answer70)
\[\int_{{}}^{{}}{\frac{\sin x\ dx}{{{(a+b\cos x)}^{2}}}=}\]
A)
\[\frac{1}{b}(a+b\cos x)+c\] done
clear
B)
\[\frac{1}{b(a+b\cos x)}+c\] done
clear
C)
\[\frac{1}{b}\log (a+b\cos x)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer71)
\[\int_{{}}^{{}}{\frac{1}{{{x}^{3}}}{{[\log {{x}^{x}}]}^{2}}\ dx=}\]
A)
\[\frac{{{x}^{3}}}{3}(\log x)+x+c\] done
clear
B)
\[\frac{1}{3}{{(\log x)}^{3}}+c\] done
clear
C)
\[3\log (\log x)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer72)
\[\int_{{}}^{{}}{\frac{1}{x}{{\sec }^{2}}(\log x)dx=}\]
A)
\[\tan (\log x)+c\] done
clear
B)
\[\log (\sec x)+c\] done
clear
C)
\[\log (\tan x)+c\] done
clear
D)
\[\sec (\log x)\ .\ \tan (\log x)+c\] done
clear
View Solution play_arrow
-
question_answer73)
\[\int_{{}}^{{}}{\frac{dx}{x\log x\log (\log x)}=}\]
A)
\[2\log (\log x)+c\] done
clear
B)
\[\log [\log (\log x)]+c\] done
clear
C)
\[\log (x\log x)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer74)
\[\int_{{}}^{{}}{\frac{{{\sec }^{2}}x\ dx}{\sqrt{{{\tan }^{2}}x+4}}=}\]
A)
\[\log \left[ \tan x+\sqrt{{{\tan }^{2}}x+4} \right]+c\] done
clear
B)
\[\frac{1}{2}\log \left[ \tan x+\sqrt{{{\tan }^{2}}x+4} \right]+c\] done
clear
C)
\[\log \left[ \frac{1}{2}\tan x+\frac{1}{2}\sqrt{{{\tan }^{2}}x+4} \right]+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer75)
\[\int_{{}}^{{}}{\frac{2x{{\tan }^{-1}}{{x}^{2}}}{1+{{x}^{4}}}}\ dx=\] [Roorkee 1982]
A)
\[{{[{{\tan }^{-1}}{{x}^{2}}]}^{2}}+c\] done
clear
B)
\[\frac{1}{2}{{[{{\tan }^{-1}}{{x}^{2}}]}^{2}}+c\] done
clear
C)
\[2{{[{{\tan }^{-1}}{{x}^{2}}]}^{2}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer76)
\[\int_{{}}^{{}}{\frac{{{a}^{\sqrt{x}}}}{\sqrt{x}}dx=}\] [Roorkee 1990; MP PET 2001]
A)
\[2{{a}^{\sqrt{x}}}{{\log }_{e}}a+c\] done
clear
B)
\[2{{a}^{\sqrt{x}}}{{\log }_{a}}e+c\] done
clear
C)
\[2{{a}^{\sqrt{x}}}{{\log }_{10}}a+c\] done
clear
D)
\[2{{a}^{\sqrt{x}}}{{\log }_{a}}10+c\] done
clear
View Solution play_arrow
-
question_answer77)
\[\int_{{}}^{{}}{\frac{{{x}^{3}}}{\sqrt{1-{{x}^{8}}}}dx=}\]
A)
\[\frac{1}{2}{{\sin }^{-1}}({{x}^{4}})+c\] done
clear
B)
\[\frac{1}{3}{{\sin }^{-1}}({{x}^{4}})+c\] done
clear
C)
\[\frac{1}{4}{{\sin }^{-1}}({{x}^{4}})+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer78)
\[\int_{{}}^{{}}{2x{{\cos }^{3}}{{x}^{2}}\sin {{x}^{2}}dx=}\]
A)
\[-\frac{1}{4}{{\cos }^{4}}{{x}^{2}}+c\] done
clear
B)
\[\frac{1}{4}{{\cos }^{4}}{{x}^{2}}+c\] done
clear
C)
\[{{\cos }^{4}}{{x}^{2}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer79)
\[\int_{{}}^{{}}{{{\sec }^{4}}x\tan x\ dx=}\] [AI CBSE 1980, 81; SCRA 1996]
A)
\[\frac{1}{4}{{\sec }^{4}}x+c\] done
clear
B)
\[4{{\sec }^{4}}x+c\] done
clear
C)
\[\frac{{{\sec }^{3}}x}{3}+c\] done
clear
D)
\[3{{\sec }^{3}}x+c\] done
clear
View Solution play_arrow
-
question_answer80)
\[\int_{{}}^{{}}{{{e}^{-x}}\text{cose}{{\text{c}}^{2}}(2{{e}^{-x}}+5)}\ dx=\] [AISSE 1988]
A)
\[\frac{1}{2}\cot (2{{e}^{-x}}+5)+c\] done
clear
B)
\[-\frac{1}{2}\cot (2{{e}^{-x}}+5)+c\] done
clear
C)
\[2\cot (2{{e}^{-x}}+5)+c\] done
clear
D)
\[-2\cot (2{{e}^{-x}}+5)+c\] done
clear
View Solution play_arrow
-
question_answer81)
\[\int_{{}}^{{}}{{{\sin }^{3}}x\ .\ \cos x\ dx=}\] [SCRA 1996]
A)
\[\frac{{{\sin }^{4}}x{{\cos }^{2}}x}{8}+c\] done
clear
B)
\[\frac{{{\sin }^{4}}x}{4}+c\] done
clear
C)
\[\frac{{{\sin }^{2}}x}{2}+c\] done
clear
D)
\[4{{\sin }^{4}}x+c\] done
clear
View Solution play_arrow
-
question_answer82)
\[\int_{{}}^{{}}{{{a}^{3x+3}}dx}=\] [Roorkee 1977]
A)
\[\frac{{{a}^{3x+3}}}{\log a}+c\] done
clear
B)
\[\frac{{{a}^{3x+3}}}{3\log a}+c\] done
clear
C)
\[{{a}^{3x+3}}\log a+c\] done
clear
D)
\[3{{a}^{3x+3}}\log a+c\] done
clear
View Solution play_arrow
-
question_answer83)
\[\int_{{}}^{{}}{\frac{\cos 2x+x+1}{{{x}^{2}}+\sin 2x+2x}}\ dx=\] [AI CBSE 1980]
A)
\[\log ({{x}^{2}}+\sin 2x+2x)+c\] done
clear
B)
\[-\log ({{x}^{2}}+\sin 2x+2x)+c\] done
clear
C)
\[\frac{1}{2}\log ({{x}^{2}}+\sin 2x+2x)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer84)
\[\int_{{}}^{{}}{\frac{1+\tan x}{x+\log \sec x}\ dx=}\] [AI CBSE 1986]
A)
\[\log (x+\log \sec x)+c\] done
clear
B)
\[-\log (x+\log \sec x)+c\] done
clear
C)
\[\log (x-\log \sec x)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer85)
\[\int_{{}}^{{}}{\frac{(x+1){{(x+\log x)}^{2}}}{x}dx=}\] [AI CBSE 1986]
A)
\[\frac{1}{3}(x+\log x)+c\] done
clear
B)
\[\frac{1}{3}{{(x+\log x)}^{2}}+c\] done
clear
C)
\[\frac{1}{3}{{(x+\log x)}^{3}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer86)
\[\int_{{}}^{{}}{\frac{1+{{x}^{2}}}{\sqrt{1-{{x}^{2}}}}dx=}\] [IIT 1977]
A)
\[\frac{3}{2}{{\sin }^{-1}}x-\frac{1}{2}x\sqrt{1-{{x}^{2}}}+c\] done
clear
B)
\[\frac{3}{2}{{\sin }^{-1}}x+\frac{1}{2}x\sqrt{1-{{x}^{2}}}+c\] done
clear
C)
\[\frac{3}{2}{{\cos }^{-1}}x-\frac{1}{2}x\sqrt{1-{{x}^{2}}}+c\] done
clear
D)
\[\frac{3}{2}{{\cos }^{-1}}x+\frac{1}{2}x\sqrt{1-{{x}^{2}}}+c\] done
clear
View Solution play_arrow
-
question_answer87)
\[\int_{{}}^{{}}{\frac{\cos x-\sin x}{1+\sin 2x}\ dx=}\] [AISSE 1985]
A)
\[-\frac{1}{\cos x+\sin x}+c\] done
clear
B)
\[\frac{1}{\cos x+\sin x}+c\] done
clear
C)
\[\frac{1}{\cos x-\sin x}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer88)
\[\int_{{}}^{{}}{{{x}^{3}}\sqrt{3+5{{x}^{4}}}}\ dx=\] [DSSE 1982]
A)
\[{{(3+5{{x}^{4}})}^{3/2}}+c\] done
clear
B)
\[\frac{1}{5}{{(3+5{{x}^{4}})}^{3/2}}+c\] done
clear
C)
\[\frac{1}{30}{{(3+5{{x}^{4}})}^{3/2}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer89)
\[\int_{{}}^{{}}{\sqrt{\frac{x}{{{a}^{3}}-{{x}^{3}}}}\ dx=}\]
A)
\[{{\sin }^{-1}}{{\left( \frac{x}{a} \right)}^{3/2}}+c\] done
clear
B)
\[\frac{2}{3}{{\sin }^{-1}}{{\left( \frac{x}{a} \right)}^{3/2}}+c\] done
clear
C)
\[\frac{3}{2}{{\sin }^{-1}}{{\left( \frac{x}{a} \right)}^{3/2}}+c\] done
clear
D)
\[\frac{3}{2}{{\sin }^{-1}}{{\left( \frac{x}{a} \right)}^{2/3}}+c\] done
clear
View Solution play_arrow
-
question_answer90)
\[\int_{{}}^{{}}{\frac{1}{x{{\cos }^{2}}(1+\log x)}\ dx=}\]
A)
\[\tan \,(1+\log x)+c\] done
clear
B)
\[\cot \,(1+\log x)+c\] done
clear
C)
\[-\tan \,(1+\log x)+c\] done
clear
D)
\[-\cot (\,1+\log x)+c\] done
clear
View Solution play_arrow
-
question_answer91)
\[\int_{{}}^{{}}{\frac{1}{{{x}^{2}}\sqrt{1+{{x}^{2}}}}}\ dx=\]
A)
\[-\frac{\sqrt{1+{{x}^{2}}}}{x}+c\] done
clear
B)
\[\frac{\sqrt{1+{{x}^{2}}}}{x}+c\] done
clear
C)
\[-\frac{\sqrt{1-{{x}^{2}}}}{x}+c\] done
clear
D)
\[-\frac{\sqrt{{{x}^{2}}-1}}{x}+c\] done
clear
View Solution play_arrow
-
question_answer92)
\[\int_{{}}^{{}}{\frac{1}{({{x}^{2}}-1)\sqrt{{{x}^{2}}+1}}}\ dx=\]
A)
\[\frac{1}{2\sqrt{2}}\log \left\{ \frac{\sqrt{1+{{x}^{2}}}+x\sqrt{2}}{\sqrt{1+{{x}^{2}}}-x\sqrt{2}} \right\}+c\] done
clear
B)
\[\frac{1}{2\sqrt{2}}\log \left\{ \frac{\sqrt{1+{{x}^{2}}}-\sqrt{2}}{\sqrt{1+{{x}^{2}}}+\sqrt{2}} \right\}+c\] done
clear
C)
\[\frac{1}{2\sqrt{2}}\log \left\{ \frac{\sqrt{1+{{x}^{2}}}-x\sqrt{2}}{\sqrt{1+{{x}^{2}}}+x\sqrt{2}} \right\}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer93)
\[\int_{{}}^{{}}{\frac{\log (x+\sqrt{1+{{x}^{2}}})}{\sqrt{1+{{x}^{2}}}}\ dx=}\]
A)
\[\frac{1}{2}{{[\log (x+\sqrt{1+{{x}^{2}}})]}^{2}}+c\] done
clear
B)
\[\log {{(x+\sqrt{1+{{x}^{2}}})}^{2}}+c\] done
clear
C)
\[\log (x+\sqrt{1+{{x}^{2}}})+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer94)
\[\int_{{}}^{{}}{{{e}^{x}}\sin ({{e}^{x}})}\ dx=\] [MP PET 1995]
A)
\[-\cos {{e}^{x}}+c\] done
clear
B)
\[\cos {{e}^{x}}+c\] done
clear
C)
\[-\text{cosec}\,{{e}^{x}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer95)
\[\int_{{}}^{{}}{\frac{{{x}^{5}}\ dx}{\sqrt{(1+{{x}^{3}})}}=}\] [IIT 1975]
A)
\[\frac{2}{3}\sqrt{(1+{{x}^{3}})}({{x}^{3}}+2)\] done
clear
B)
\[\frac{2}{9}\sqrt{(1+{{x}^{3}})}({{x}^{3}}-4)\] done
clear
C)
\[\frac{2}{9}\sqrt{(1+{{x}^{3}})}({{x}^{3}}+4)\] done
clear
D)
\[\frac{2}{9}\sqrt{(1+{{x}^{3}})}({{x}^{3}}-2)\] done
clear
View Solution play_arrow
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question_answer96)
\[\int_{{}}^{{}}{\frac{{{({{x}^{4}}-x)}^{1/4}}}{{{x}^{5}}}\ dx}\] is equal to
A)
\[\frac{4}{15}{{\left( 1-\frac{1}{{{x}^{3}}} \right)}^{5/4}}+c\] done
clear
B)
\[\frac{4}{5}{{\left( 1-\frac{1}{{{x}^{3}}} \right)}^{5/4}}+c\] done
clear
C)
\[\frac{4}{15}{{\left( 1+\frac{1}{{{x}^{3}}} \right)}^{5/4}}+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer97)
\[\int_{{}}^{{}}{\frac{1}{{{[{{(x-1)}^{3}}{{(x+2)}^{5}}]}^{1/4}}}\ dx}\] is equal to
A)
\[\frac{4}{3}{{\left( \frac{x-1}{x+2} \right)}^{1/4}}+c\] done
clear
B)
\[\frac{4}{3}{{\left( \frac{x+2}{x-1} \right)}^{1/4}}+c\] done
clear
C)
\[\frac{1}{3}{{\left( \frac{x-1}{x+2} \right)}^{1/4}}+c\] done
clear
D)
\[\frac{1}{3}{{\left( \frac{x+2}{x-1} \right)}^{1/4}}+c\] done
clear
View Solution play_arrow
-
question_answer98)
\[\int_{{}}^{{}}{\frac{1}{1+{{\sin }^{2}}x}\ dx=}\]
A)
\[\frac{1}{\sqrt{2}}{{\tan }^{-1}}(\sqrt{2}\tan x)+k\] done
clear
B)
\[\sqrt{2}{{\tan }^{-1}}(\sqrt{2}\tan x)+k\] done
clear
C)
\[-\frac{1}{\sqrt{2}}{{\tan }^{-1}}(\sqrt{2}\tan x)+k\] done
clear
D)
\[-\sqrt{2}{{\tan }^{-1}}(\sqrt{2}\tan x)+k\] done
clear
View Solution play_arrow
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question_answer99)
The value of \[\int_{{}}^{{}}{\frac{\sin x}{{{\cos }^{2}}x}\ dx}\] is
A)
\[\sin x+k\] done
clear
B)
\[\tan x+k\] done
clear
C)
\[\sec x+k\] done
clear
D)
\[\tan x+\sec x+k\] done
clear
View Solution play_arrow
-
question_answer100)
The value of\[\int_{{}}^{{}}{{{e}^{x}}{{\sec }^{2}}({{e}^{x}})\ dx}\] is
A)
\[\tan ({{e}^{x}})+k\] done
clear
B)
\[\tan ({{e}^{x}})\ .\ e+k\] done
clear
C)
\[{{e}^{x}}\tan x+k\] done
clear
D)
\[\frac{\tan ({{e}^{x}})}{{{e}^{x}}}+k\] done
clear
View Solution play_arrow
-
question_answer101)
The value of \[\int_{{}}^{{}}{\frac{dx}{x\sqrt{{{x}^{4}}-1}}}\] is
A)
\[\frac{1}{2}{{\sec }^{-1}}{{x}^{2}}+k\] done
clear
B)
\[\log x\sqrt{{{x}^{4}}-1}+k\] done
clear
C)
\[x\log \sqrt{{{x}^{4}}-1}+k\] done
clear
D)
\[\log \sqrt{{{x}^{4}}-1}+k\] done
clear
View Solution play_arrow
-
question_answer102)
\[\int_{{}}^{{}}{\frac{t}{{{e}^{3{{t}^{2}}}}}\ dt=}\] [MP PET 1997]
A)
\[\frac{1}{6}{{e}^{3{{t}^{2}}}}+c\] done
clear
B)
\[-\frac{1}{6}{{e}^{3{{t}^{2}}}}+c\] done
clear
C)
\[\frac{1}{6}{{e}^{-3{{t}^{2}}}}+c\] done
clear
D)
\[-\frac{1}{6}{{e}^{-3{{t}^{2}}}}+c\] done
clear
View Solution play_arrow
-
question_answer103)
If \[\int_{{}}^{{}}{\frac{1}{(1+x)\sqrt{x}}\ dx=f(x)+A}\], where A is any arbitrary constant, then the function \[f(x)\] is [MP PET 1998]
A)
\[2{{\tan }^{-1}}x\] done
clear
B)
\[2{{\tan }^{-1}}\sqrt{x}\] done
clear
C)
\[2{{\cot }^{-1}}\sqrt{x}\] done
clear
D)
\[{{\log }_{e}}(1+x)\] done
clear
View Solution play_arrow
-
question_answer104)
\[\int_{{}}^{{}}{x\cos {{x}^{2}}\ dx}\] is equal to [MP PET 1999; Pb. CET 2000]
A)
\[-\frac{1}{2}{{\sin }^{2}}x+c\] done
clear
B)
\[\frac{1}{2}{{\sin }^{2}}x+c\] done
clear
C)
\[-\frac{1}{2}\sin {{x}^{2}}+c\] done
clear
D)
\[\frac{1}{2}\sin {{x}^{2}}+c\] done
clear
View Solution play_arrow
-
question_answer105)
\[\int_{{}}^{{}}{\frac{{{x}^{2}}{{\tan }^{-1}}{{x}^{3}}}{1+{{x}^{6}}}\ dx}\] is equal to [MP PET 1999; UPSEAT 1999]
A)
\[{{\tan }^{-1}}({{x}^{3}})+c\] done
clear
B)
\[\frac{1}{6}{{({{\tan }^{-1}}{{x}^{3}})}^{2}}+c\] done
clear
C)
\[-\frac{1}{2}{{({{\tan }^{-1}}{{x}^{3}})}^{2}}+c\] done
clear
D)
\[\frac{1}{2}{{({{\tan }^{-1}}{{x}^{2}})}^{3}}+c\] done
clear
View Solution play_arrow
-
question_answer106)
\[\int_{{}}^{{}}{\frac{{{x}^{2}}+1}{x({{x}^{2}}-1)}\ dx}\] is equal to [MP PET 1999]
A)
\[\log \frac{{{x}^{2}}-1}{x}+c\] done
clear
B)
\[-\log \frac{{{x}^{2}}-1}{x}+c\] done
clear
C)
\[\log \frac{x}{{{x}^{2}}+1}+c\] done
clear
D)
\[-\log \frac{x}{{{x}^{2}}+1}+c\] done
clear
View Solution play_arrow
-
question_answer107)
\[\int_{{}}^{{}}{\frac{{{e}^{2x}}+1}{{{e}^{2x}}-1}\ dx}\] equals [RPET 1996]
A)
\[\log ({{e}^{x}}-{{e}^{-x}})+c\] done
clear
B)
\[\log ({{e}^{x}}+{{e}^{-x}})+c\] done
clear
C)
\[\log ({{e}^{-x}}-{{e}^{x}})+c\] done
clear
D)
\[\log (1-{{e}^{-x}})+c\] done
clear
View Solution play_arrow
-
question_answer108)
\[\int_{{}}^{{}}{\frac{\cos x-\sin x}{\sqrt{\sin 2x}}\ dx}\] equals [RPET 1996]
A)
\[{{\cosh }^{-1}}(\sin x+\cos x)+c\] done
clear
B)
\[{{\sinh }^{-1}}(\sin x+\cos x)+c\] done
clear
C)
\[-{{\cosh }^{-1}}(\sin x+\cos x)+c\] done
clear
D)
\[-{{\sinh }^{-1}}(\sin x+\cos x)+c\] done
clear
View Solution play_arrow
-
question_answer109)
The value of \[\int_{{}}^{{}}{\left( 1+\frac{1}{{{x}^{2}}} \right)\ {{e}^{\left( x-\frac{1}{x} \right)}}}\ dx\] equals [Kurukshetra CEE 1998]
A)
\[{{e}^{x-\frac{1}{x}}}+c\] done
clear
B)
\[{{e}^{x+\frac{1}{x}}}+c\] done
clear
C)
\[{{e}^{{{x}^{2}}-\frac{1}{x}}}+c\] done
clear
D)
\[{{e}^{{{x}^{2}}+\frac{1}{{{x}^{2}}}}}+c\] done
clear
View Solution play_arrow
-
question_answer110)
\[\int_{{}}^{{}}{(x+3){{({{x}^{2}}+6x+10)}^{9}}\ dx}\] equals [SCRA 1996]
A)
\[\frac{1}{20}{{({{x}^{2}}+6x+10)}^{10}}+c\] done
clear
B)
\[\frac{1}{20}{{(x+3)}^{2}}{{({{x}^{2}}+6x+10)}^{10}}+c\] done
clear
C)
\[\frac{1}{16}{{({{x}^{2}}+6x+10)}^{8}}+c\] done
clear
D)
\[\frac{1}{38}{{(x+3)}^{19}}+\frac{1}{2}(x+3)+c\] done
clear
View Solution play_arrow
-
question_answer111)
A primitive of \[\frac{x}{{{x}^{2}}+1}\] is [SCRA 1996]
A)
\[{{\log }_{e}}({{x}^{2}}+1)\] done
clear
B)
\[x{{\tan }^{-1}}x\] done
clear
C)
\[\frac{{{\log }_{e}}({{x}^{2}}+1)}{2}\] done
clear
D)
\[\frac{1}{2}x{{\tan }^{-1}}x\] done
clear
View Solution play_arrow
-
question_answer112)
\[\int_{{}}^{{}}{{{\sin }^{3}}x\ dx}\] is equal to [SCRA 1996]
A)
\[{{\sin }^{2}}x+1\] done
clear
B)
\[\sin {{x}^{2}}+{{x}^{2}}+1\] done
clear
C)
\[\frac{{{\cos }^{3}}x}{3}-\cos x\] done
clear
D)
\[\frac{1}{4}{{\sin }^{4}}x-\frac{3}{4}{{\sin }^{2}}x\] done
clear
View Solution play_arrow
-
question_answer113)
\[\int_{{}}^{{}}{\frac{1}{x}\log x\ dx}\] is equal to [SCRA 1996]
A)
\[\frac{1}{2}\log x+c\] done
clear
B)
\[\frac{1}{2}{{(\log x)}^{2}}+c\] done
clear
C)
\[\frac{1}{2}\log {{(x)}^{2}}+c\] done
clear
D)
\[\log x+c\] done
clear
View Solution play_arrow
-
question_answer114)
\[\int_{{}}^{{}}{{{\sin }^{2}}x\cos x\ dx}\] is equal to [SCRA 1996]
A)
\[\frac{{{\cos }^{2}}x}{2}+c\] done
clear
B)
\[\frac{{{\sin }^{2}}x}{3}+c\] done
clear
C)
\[\frac{{{\sin }^{3}}x}{3}+c\] done
clear
D)
\[-\frac{{{\cos }^{2}}x}{2}+c\] done
clear
View Solution play_arrow
-
question_answer115)
\[\int_{{}}^{{}}{{{e}^{{{x}^{2}}}}x\ dx}\] is equal to [SCRA 1996]
A)
\[{{e}^{{{x}^{2}}}}\] done
clear
B)
\[\frac{1}{2}{{e}^{{{x}^{2}}}}\] done
clear
C)
\[2{{e}^{{{x}^{2}}}}\] done
clear
D)
\[\frac{{{e}^{{{x}^{2}}}}-{{x}^{2}}}{2}\] done
clear
View Solution play_arrow
-
question_answer116)
The value of \[\int_{{}}^{{}}{\frac{{{x}^{3}}}{\sqrt{1+{{x}^{4}}}}\ dx}\] is [SCRA 1996]
A)
\[{{(1+{{x}^{4}})}^{\frac{1}{2}}}+c\] done
clear
B)
\[-{{(1+{{x}^{4}})}^{\frac{1}{2}}}+c\] done
clear
C)
\[\frac{1}{2}{{(1+{{x}^{4}})}^{\frac{1}{2}}}+c\] done
clear
D)
\[-\frac{1}{2}{{(1+{{x}^{4}})}^{\frac{1}{2}}}+c\] done
clear
View Solution play_arrow
-
question_answer117)
What is the value of the integral \[I=\int{\frac{dx}{(1+{{e}^{x}})\,\,(1+{{e}^{-x}})}}\] [DCE 1999]
A)
\[\frac{-1}{1+{{e}^{x}}}\] done
clear
B)
\[\frac{{{e}^{x}}}{1+{{e}^{x}}}\] done
clear
C)
\[\frac{1}{1+{{e}^{x}}}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer118)
\[\int{\frac{{{e}^{\sqrt{x}}}}{\sqrt{x}}dx}=\] [DCE 1999]
A)
\[{{e}^{\sqrt{x}}}\] done
clear
B)
\[\frac{{{e}^{\sqrt{x}}}}{2}\] done
clear
C)
\[2\,{{e}^{\sqrt{x}}}\] done
clear
D)
\[\sqrt{x}\,.\,{{e}^{\sqrt{x}}}\] done
clear
View Solution play_arrow
-
question_answer119)
\[\int{\frac{{{\sin }^{3}}2x}{{{\cos }^{5}}2x}dx=}\] [Karnataka CET 1999]
A)
\[{{\tan }^{4}}x+C\] done
clear
B)
\[\tan 4x+C\] done
clear
C)
\[{{\tan }^{4}}2x+x+C\] done
clear
D)
\[\frac{1}{8}{{\tan }^{4}}2x+C\] done
clear
View Solution play_arrow
-
question_answer120)
\[\int{{{x}^{x}}(1+\log x)\,\,dx}\] is equal to [RPET 2000]
A)
\[{{x}^{x}}\] done
clear
B)
\[{{x}^{2x}}\] done
clear
C)
\[{{x}^{x}}\log x\] done
clear
D)
\[\frac{1}{2}{{(1+\log x)}^{2}}\] done
clear
View Solution play_arrow
-
question_answer121)
\[\int{\frac{dx}{{{({{a}^{2}}+{{x}^{2}})}^{3/2}}}}\] is equal to [RPET 2000]
A)
\[\frac{x}{{{\left( {{a}^{2}}+{{x}^{2}} \right)}^{1/2}}}\] done
clear
B)
\[\frac{x}{{{a}^{2}}{{\left( {{a}^{2}}+{{x}^{2}} \right)}^{1/2}}}\] done
clear
C)
\[\frac{1}{{{a}^{2}}{{\left( {{a}^{2}}+{{x}^{2}} \right)}^{1/2}}}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer122)
\[\int_{{}}^{{}}{\frac{{{e}^{m{{\tan }^{-1}}x}}}{1+{{x}^{2}}}dx}\] equals to [RPET 2001]
A)
\[{{e}^{{{\tan }^{-1}}x}}\] done
clear
B)
\[\frac{1}{m}{{e}^{{{\tan }^{-1}}x}}\] done
clear
C)
\[\frac{1}{m}{{e}^{m{{\tan }^{-1}}x}}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer123)
\[\int{\frac{1+{{\tan }^{2}}x}{1-{{\tan }^{2}}x}\,dx}\] equals to [RPET 2001]
A)
\[\log \left( \frac{1-\tan x}{1+\tan x} \right)+c\] done
clear
B)
\[\log \left( \frac{1+\tan x}{1-\tan x} \right)+c\] done
clear
C)
\[\frac{1}{2}\log \left( \frac{1-\tan x}{1+\tan x} \right)+c\] done
clear
D)
\[\frac{1}{2}\log \left( \frac{1+\tan x}{1-\tan x} \right)+c\] done
clear
View Solution play_arrow
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question_answer124)
The value of \[\int{\frac{2\,\,dx}{\sqrt{1-4{{x}^{2}}}}}\] is [Karnataka CET 2001; Pb. CET 2001]
A)
\[{{\tan }^{-1}}(2x)+c\] done
clear
B)
\[{{\cot }^{-1}}(2x)+c\] done
clear
C)
\[{{\cos }^{-1}}(2x)+c\] done
clear
D)
\[{{\sin }^{-1}}(2x)+c\] done
clear
View Solution play_arrow
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question_answer125)
\[\int{{{e}^{3\log x}}{{({{x}^{4}}+1)}^{-1}}\,\,dx}\]= [MP PET 2001]
A)
\[\log ({{x}^{4}}+1)+c\] done
clear
B)
\[\frac{1}{4}\log ({{x}^{4}}+1)+c\] done
clear
C)
\[-\log ({{x}^{4}}+1)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer126)
\[\int_{{}}^{{}}{\frac{dx}{2\sqrt{x}(1+x)}=}\] [RPET 2002]
A)
\[\frac{1}{2}{{\tan }^{-1}}(\sqrt{x})+c\] done
clear
B)
\[{{\tan }^{-1}}(\sqrt{x})+c\] done
clear
C)
\[2{{\tan }^{-1}}(\sqrt{x})+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer127)
\[\int{\text{cose}{{\text{c}}^{4}}x\,dx}=\] [RPET 2002]
A)
\[\cot x+\frac{{{\cot }^{3}}x}{3}+c\] done
clear
B)
\[\tan x+\frac{{{\tan }^{3}}x}{3}+c\] done
clear
C)
\[-\cot x-\frac{{{\cot }^{3}}x}{3}+c\] done
clear
D)
\[-\tan x-\frac{{{\tan }^{3}}x}{3}+c\] done
clear
View Solution play_arrow
-
question_answer128)
\[\int{x{{e}^{{{x}^{2}}}}}dx=\] [RPET 2003]
A)
\[-\frac{{{e}^{{{x}^{2}}}}}{2}+c\] done
clear
B)
\[\frac{{{e}^{{{x}^{2}}}}}{2}+c\] done
clear
C)
\[\frac{{{e}^{x}}}{2}+c\] done
clear
D)
\[-\frac{{{e}^{x}}}{2}+c\] done
clear
View Solution play_arrow
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question_answer129)
. If \[\int{f(x)\,\,dx=g(x),}\] then \[\int{{{f}^{-1}}(x)}\,\,dx\] is equal to [MP PET 2003]
A)
\[{{g}^{-1}}(x)\] done
clear
B)
\[x{{f}^{-1}}(x)-g({{f}^{-1}}(x))\] done
clear
C)
\[x{{f}^{-1}}(x)-{{g}^{-1}}(x)\] done
clear
D)
\[{{f}^{-1}}(x)\] done
clear
View Solution play_arrow
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question_answer130)
The value of \[\int_{{}}^{{}}{\frac{{{e}^{x}}}{{{e}^{x}}+1}}\,dx\] is [Pb. CET 2000]
A)
\[{{e}^{x}}+c\] done
clear
B)
\[({{e}^{x}}+1)+c\] done
clear
C)
\[\log ({{e}^{x}}+1)+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer131)
The value of \[\int_{{}}^{{}}{\frac{\sin x-\cos x}{\sin x+\cos x}\,dx}\] is [Pb. CET 2000]
A)
\[\frac{1}{\sin x+\cos x}+c\] done
clear
B)
\[\frac{1}{\sin x-\cos x}+c\] done
clear
C)
\[\log (\sin x+\cos x)+c\] done
clear
D)
\[\log \left( \frac{1}{\sin x+\cos x} \right)+c\] done
clear
View Solution play_arrow
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question_answer132)
\[\int_{{}}^{{}}{\frac{{{({{\tan }^{-1}}x)}^{3}}}{1+{{x}^{2}}}\,dx=}\] [UPSEAT 2004]
A)
\[{{({{\tan }^{-1}}x)}^{4}}+c\] done
clear
B)
\[\frac{{{({{\tan }^{-1}}x)}^{4}}}{4}+c\] done
clear
C)
\[2{{\tan }^{-1}}x+c\] done
clear
D)
\[2{{({{\tan }^{-1}}x)}^{2}}+c\] done
clear
View Solution play_arrow
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question_answer133)
\[\int_{{}}^{{}}{\sqrt{\frac{1-x}{1+x}}}\ dx=\] [IIT 1971]
A)
\[{{\sin }^{-1}}x-\frac{1}{2}\sqrt{1-{{x}^{2}}}+c\] done
clear
B)
\[{{\sin }^{-1}}x+\frac{1}{2}\sqrt{1-{{x}^{2}}}+c\] done
clear
C)
\[{{\sin }^{-1}}x-\sqrt{1-{{x}^{2}}}+c\] done
clear
D)
\[{{\sin }^{-1}}x+\sqrt{1-{{x}^{2}}}+c\] done
clear
View Solution play_arrow
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question_answer134)
\[\int_{{}}^{{}}{\frac{\sqrt{x}}{1+x}dx=}\]
A)
\[\sqrt{x}-{{\tan }^{-1}}\sqrt{x}+c\] done
clear
B)
\[2(\sqrt{x}-{{\tan }^{-1}}\sqrt{x})+c\] done
clear
C)
\[2(\sqrt{x}+{{\tan }^{-1}}x)+c\] done
clear
D)
\[\sqrt{1+x}+c\] done
clear
View Solution play_arrow
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question_answer135)
\[\int_{{}}^{{}}{\frac{\sin x}{\sin x-\cos x}}\ dx=\] [Roorkee 1988]
A)
\[\frac{1}{2}\log (\sin x-\cos x)+x+c\] done
clear
B)
\[\frac{1}{2}[\log (\sin x-\cos x)+x]+c\] done
clear
C)
\[\frac{1}{2}\log (\cos x-\sin x)+x+c\] done
clear
D)
\[\frac{1}{2}[\log (\cos x-\sin x)+x]+c\] done
clear
View Solution play_arrow
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question_answer136)
\[\int{\sqrt{\frac{1+x}{1-x}}\,\,dx=}\] [RPET 2002]
A)
\[-{{\sin }^{-1}}x-\sqrt{1-{{x}^{2}}}\,+c\] done
clear
B)
\[{{\sin }^{-1}}x+\sqrt{1-{{x}^{2}}}\,+c\] done
clear
C)
\[{{\sin }^{-1}}x-\sqrt{1-{{x}^{2}}}\,+c\] done
clear
D)
\[-{{\sin }^{-1}}x-\sqrt{{{x}^{2}}-1}\,+c\] done
clear
View Solution play_arrow
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question_answer137)
\[\int_{{}}^{{}}{\frac{x}{\sqrt{4-{{x}^{4}}}}dx}=\] [Roorkee 1976]
A)
\[{{\cos }^{-1}}\frac{{{x}^{2}}}{2}\] done
clear
B)
\[\frac{1}{2}{{\cos }^{-1}}\frac{{{x}^{2}}}{2}\] done
clear
C)
\[{{\sin }^{-1}}\frac{{{x}^{2}}}{2}\] done
clear
D)
\[\frac{1}{2}{{\sin }^{-1}}\frac{{{x}^{2}}}{2}\] done
clear
View Solution play_arrow
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question_answer138)
\[\int{\frac{\sin x\,\,dx}{3+4{{\cos }^{2}}x}=}\] [Karnataka CET 2000]
A)
\[\log (3+4{{\cos }^{2}}x)+c\] done
clear
B)
\[\frac{-1}{2\sqrt{3}}{{\tan }^{-1}}\left( \frac{\cos x}{\sqrt{3}} \right)+c\] done
clear
C)
\[\frac{-1}{2\sqrt{3}}{{\tan }^{-1}}\left( \frac{2\cos x}{\sqrt{3}} \right)+c\] done
clear
D)
\[\frac{1}{2\sqrt{3}}{{\tan }^{-1}}\left( \frac{2\cos x}{\sqrt{3}} \right)+c\] done
clear
View Solution play_arrow
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question_answer139)
The value of \[\int_{{}}^{{}}{\frac{dx}{\sqrt{x}\,(x+9)}dx}\] is equal to [Pb. CET 2002]
A)
\[{{\tan }^{-1}}\sqrt{x}\] done
clear
B)
\[{{\tan }^{-1}}\left( \frac{\sqrt{x}}{3} \right)\] done
clear
C)
\[\frac{2}{3}{{\tan }^{-1}}\sqrt{x}\] done
clear
D)
\[\frac{2}{3}{{\tan }^{-1}}\left( \frac{\sqrt{x}}{3} \right)\] done
clear
View Solution play_arrow
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question_answer140)
\[{{\int{\left\{ \frac{(\log x-1)}{1+{{(\log x)}^{2}}} \right\}}}^{2}}dx\] is equal to [AIEEE 2005]
A)
\[\frac{x{{e}^{x}}}{1+{{x}^{2}}}+c\] done
clear
B)
\[\frac{x}{{{(\log x)}^{2}}+1}+C\] done
clear
C)
\[\frac{\log x}{{{(\log x)}^{2}}+1}+c\] done
clear
D)
\[\frac{x}{{{x}^{2}}+1}+c\] done
clear
View Solution play_arrow
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question_answer141)
\[\int_{{}}^{{}}{\frac{\sin 2xdx}{1+{{\cos }^{2}}x}}=\] [Karnataka CET 2005]
A)
\[\frac{1}{2}\log (1+{{\cos }^{2}}x)+c\] done
clear
B)
\[2\log (1+{{\cos }^{2}}x)+c\] done
clear
C)
\[\frac{1}{2}\log (1+\cos 2x)+c\] done
clear
D)
\[-\log (1+{{\cos }^{2}}x)+c\] done
clear
View Solution play_arrow
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question_answer142)
If \[\int{\frac{\cos 4x+1}{\cos x-\tan x}}dx=k\,\,\cos 4x+c\] then [DCE 2005]
A)
\[k=-1/2\] done
clear
B)
\[k=-1/8\] done
clear
C)
\[k=-1/4\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer143)
If \[\int{\frac{1}{x+{{x}^{5}}}dx=f(x)+c}\], then the value of \[\int{\frac{{{x}^{4}}}{x+{{x}^{5}}}dx}\] is [DCE 2005]
A)
\[\log x-f(x)+c\] done
clear
B)
\[f(x)+\log x+c\] done
clear
C)
\[f(x)-\log x+c\] done
clear
D)
None of these done
clear
View Solution play_arrow
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question_answer144)
Let \[f(x)=\int{\frac{{{x}^{2}}dx}{(1+{{x}^{2}})\,\left( 1+\sqrt{1+{{x}^{2}}} \right)}}\]and \[f(0)=0\], then the value of \[f(1)\] be [AMU 2005]
A)
\[\log (1+\sqrt{2})\] done
clear
B)
\[\log (1+\sqrt{2})-\frac{\pi }{4}\] done
clear
C)
\[\log (1+\sqrt{2})+\frac{\pi }{2}\] done
clear
D)
None of these done
clear
View Solution play_arrow
-
question_answer145)
\[\int{\sqrt{{{e}^{x}}-1}}dx=\] [Kerala (Engg.) 2005]
A)
\[2\left[ \sqrt{{{e}^{x}}-1}-{{\tan }^{-1}}\sqrt{{{e}^{x}}-1} \right]+c\] done
clear
B)
\[\sqrt{{{e}^{x}}-1}-{{\tan }^{-1}}\sqrt{{{e}^{x}}-1}+c\] done
clear
C)
\[\sqrt{{{e}^{x}}-1}+{{\tan }^{-1}}\sqrt{{{e}^{x}}-1}+c\] done
clear
D)
\[2\left[ \sqrt{{{e}^{x}}-1}+{{\tan }^{-1}}\sqrt{{{e}^{x}}-1} \right]+c\] done
clear
E)
\[2\left[ \sqrt{{{e}^{x}}-1}-{{\tan }^{-1}}\sqrt{{{e}^{x}}+1} \right]+c\] done
clear
View Solution play_arrow
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question_answer146)
\[\int{\frac{dx}{\sin (x-a)\sin (x-b)}}\] is [Kerala (Engg.) 2005]
A)
\[\frac{1}{\sin (a-b)}\log \left| \frac{\sin (x-a)}{\sin (x-b)} \right|+c\] done
clear
B)
\[\frac{-1}{\sin (a-b)}\log \left| \frac{\sin (x-a)}{\sin (x-b)} \right|+c\] done
clear
C)
\[\log \sin (x-a)\sin (x-b)+c\] done
clear
D)
\[\log \left| \frac{\sin (x-a)}{\sin (x-b)} \right|\] done
clear
E)
\[\frac{1}{\sin (x-a)}\log \sin (x-a)\sin (x-b)+c\] done
clear
View Solution play_arrow
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question_answer147)
\[\int{\frac{(\sin \theta +\cos \theta )}{\sqrt{\sin 2\theta }}}d\theta =\] [Kerala (Engg.) 2005]
A)
\[\log \left| \cos \theta -\sin \theta +\sqrt{\sin 2\theta } \right|\] done
clear
B)
\[\log \left| \sin \theta -\cos \theta )+\sqrt{\sin 2\theta } \right|\] done
clear
C)
\[{{\sin }^{-1}}(\sin \theta -\cos \theta )+c\] done
clear
D)
\[{{\sin }^{-1}}(\sin \theta +\cos \theta )+c\] done
clear
E)
\[{{\sin }^{-1}}(\cos \theta -\sin \theta )+c\] done
clear
View Solution play_arrow
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question_answer148)
\[\int{{{\cos }^{-3/7}}}x{{\sin }^{-11/7}}x\,\,dx=\] [Kerala (Engg.) 2005]
A)
\[\log |{{\sin }^{4/7}}x|+c\] done
clear
B)
\[\frac{4}{7}{{\tan }^{4/7}}x+c\] done
clear
C)
\[\frac{-7}{4}{{\tan }^{-4/7}}x+c\] done
clear
D)
\[\log |{{\cos }^{3/7}}x|+c\] done
clear
E)
\[\frac{7}{4}{{\tan }^{-4/7}}x+C\] done
clear
View Solution play_arrow