A) \[[Co{{(N{{H}_{3}})}_{4}}S{{O}_{4}}]N{{O}_{2}}\]
B) \[[Cr{{\left( N{{H}_{3}} \right)}_{5}}S{{O}_{4}}]Cl\]
C) \[[Cr{{(N{{H}_{3}})}_{5}}Cl]S{{O}_{4}}\]
D) Both B and C
Correct Answer: C
Solution :
\[[Cr{{(N{{H}_{3}})}_{5}}Cl]S{{O}_{4}}\to {{[Cr{{(N{{H}_{3}})}_{5}}Cl]}^{2+}}+SO_{4}^{2-}\] \[{{(Cr\,{{(N{{H}_{3}})}_{5}}Cl]}^{2+}}+SO_{4}^{2-}+BaC{{l}_{2}}\to \] \[[Cr\,{{(N{{H}_{3}})}_{5}}Cl]\,C{{l}_{2}}+BaS{{O}_{4}}+HCl\].
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