A) \[\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Cl \right]\,{{\left( N{{O}_{2}} \right)}_{2}}\]
B) \[\left[ Pt{{\left( N{{H}_{3}} \right)}_{2}}C{{l}_{2}} \right]\]
C) \[\left[ Pt(en)C{{l}_{2}} \right]\]
D) \[\left[ Pt{{\left( N{{H}_{3}} \right)}_{4}} \right]\,C{{l}_{2}}\]
Correct Answer: D
Solution :
\[[Pt\,{{(N{{H}_{3}})}_{4}}]\,C{{l}_{2}}\to {{[Pt\,{{(N{{H}_{3}})}_{4}}]}^{+2}}+2C{{l}^{-}}\] As it gives \[C{{l}^{-}}\] ions in solution so it will give white ppt. of \[AgCl\] with\[AgN{{O}_{3}}\].
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