A) \[\left[ Cr{{\left( N{{H}_{3}} \right)}_{6}} \right]C{{l}_{3}}\]
B) \[\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Br \right]S{{O}_{4}}\]
C) \[\left[ Cr{{(en)}_{2}}C{{l}_{2}} \right]\]
D) \[\left[ Cr{{(en)}_{3}}C{{l}_{3}} \right]\]
Correct Answer: B
Solution :
The compound which has same composition but give different ions in solution, show ionization. So \[[Co{{(N{{H}_{3}})}_{5}}Br]\]\[SO_{4}^{{}}\]is ionization isomer. \[[Co{{(N{{H}_{3}})}_{5}}Br]S{{O}_{4}}\]⇌ \[{{[Co{{(N{{H}_{3}})}_{5}}Br]}^{2+}}+SO_{4}^{2-}\] \[[Co{{(N{{H}_{3}})}_{5}}S{{O}_{4}}]Br\]⇌ \[{{[Co(N{{H}_{3}})S{{O}_{4}}]}^{+}}+B{{r}^{-}}\].
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