A) \[5/6\]
B) \[7/6\]
C) \[1/6\]
D) \[1/7\]
Correct Answer: D
Solution :
\[\tan \left[ {{\tan }^{-1}}\frac{1}{2}-{{\tan }^{-1}}\frac{1}{3} \right]\] = \[\tan \left[ {{\tan }^{-1}}\frac{\frac{1}{2}-\frac{1}{3}}{1+\frac{1}{6}} \right]\] = \[\tan {{\tan }^{-1}}\left( \frac{1}{6}\times \frac{6}{7} \right)\]= \[\frac{1}{7}\].
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