A) \[\frac{\pi }{4}\]
B) \[\frac{\pi }{6}\]
C) \[\frac{\pi }{3}\]
D) \[\frac{2\pi }{3}\]
Correct Answer: D
Solution :
\[{{\cos }^{-1}}\frac{1}{2}+2{{\sin }^{-1}}\frac{1}{2}=\frac{\pi }{3}+\frac{2\pi }{6}=\frac{2\pi }{3}\].
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