JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    If \[{{\cos }^{-1}}\frac{3}{5}-{{\sin }^{-1}}\frac{4}{5}={{\cos }^{-1}}x,\]then x =  [AMU 1978]

    A) 0

    B) 1

    C) -1

    D) 2

    Correct Answer: B

    Solution :

      \[{{\cos }^{-1}}\frac{3}{5}-{{\sin }^{-1}}\frac{4}{5}={{\cos }^{-1}}x\] \[\Rightarrow {{\cos }^{-1}}\frac{3}{5}-{{\cos }^{-1}}\sqrt{1-\frac{16}{25}}={{\cos }^{-1}}x\] \[\Rightarrow {{\cos }^{-1}}\frac{3}{5}-{{\cos }^{-1}}\frac{3}{5}={{\cos }^{-1}}x\] \[\Rightarrow {{\cos }^{-1}}x=0\Rightarrow x=1\].


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