A) 10
B) \[10-3\pi \]
C) \[3\pi -10\]
D) None of these
Correct Answer: C
Solution :
Since \[3\pi <10<3\pi +\frac{\pi }{2}\,\,\Rightarrow \,0<10-3\pi <\frac{\pi }{2}\] \[\Rightarrow \,\,\frac{-\pi }{2}<3\pi -10<0\]\[\Rightarrow \,\,{{\sin }^{-1}}\left\{ \sin \,(3\pi -10) \right\}=3\pi -10\].
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