A) \[\frac{7\pi }{6}\]
B) \[\frac{5\pi }{6}\]
C) \[\frac{\pi }{6}\]
D) None of these
Correct Answer: B
Solution :
\[{{\cos }^{-1}}\left( \cos \frac{7\pi }{6} \right)={{\cos }^{-1}}\left\{ \cos \left( \pi +\frac{\pi }{6} \right) \right\}\] = \[{{\cos }^{-1}}\left( -\cos \frac{\pi }{6} \right)=\pi -{{\cos }^{-1}}\cos \frac{\pi }{6}=\pi -\frac{\pi }{6}=\frac{5\pi }{6}\].
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