JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    The principal value of \[{{\sin }^{-1}}\left( -\frac{1}{2} \right)\]is

    A) \[\frac{\pi }{3}\]

    B) \[\frac{\pi }{6}\]

    C) \[-\frac{\pi }{3}\]

    D) \[-\frac{\pi }{6}\]

    Correct Answer: D

    Solution :

    The principal value of \[{{\sin }^{-1}}\left( -\frac{1}{2} \right)={{\sin }^{-1}}\,\sin \,(-{{30}^{o}})\] \[=-\frac{\pi }{6}\].


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