A) \[\sqrt{3}\]
B) \[\frac{1}{\sqrt{3}}\]
C) \[\frac{1}{\sqrt{2}}\]
D) None of these
Correct Answer: B
Solution :
Given that \[{{\sin }^{-1}}\frac{1}{2}={{\tan }^{-1}}x\] \[\Rightarrow \,\,{{\tan }^{-1}}x=\frac{\pi }{6}\]\[\Rightarrow \,\,x=\tan {{30}^{o}}=\frac{1}{\sqrt{3}}\].
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