A) \[\frac{1}{\sqrt{1-{{\sin }^{2}}\theta }}\]
B) \[\frac{\sqrt{1-{{\sin }^{2}}\theta }}{\sin \theta }\]
C) \[\frac{1}{\sin \theta }\]
D) \[\frac{\sin \theta }{\sqrt{1-{{\sin }^{2}}\theta }}\]
Correct Answer: B
Solution :
\[{{6}^{x}}\]
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