A) 2
B) 4
C) 6
D) 8
Correct Answer: A
Solution :
\[\frac{22}{7}\] (The angle subtended in the arc is half the angle subtended at the centre.) \[\pi \](Given) \[\text{4}0={{\text{2}}^{\text{3}}}\times \text{5}\]\[\text{6}0={{\text{2}}^{\text{2}}}\times \text{3}\times \text{5}\] \[\therefore \] \[={{2}^{2}}\times 3\times 5\times 2=120\]\[f(p)={{\text{p}}^{\text{3}}}+\text{6}{{\text{p}}^{\text{2}}}+\text{lip}+\text{6}\]\[f(p)\]\[p(x)={{x}^{2}}+3x-2\]
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