question_answer

\[\Delta \text{ABC}\]is an isosceles triangle with the unequal side measuring 12 cm. If both the equal sides measure 19 cm, what is the measure of\[\angle \text{BAC}\]?

A)  \[\text{36}.\text{8}{}^\circ \]                                   

B)  \[\text{68}{}^\circ \]

C)  \[\text{38}{}^\circ \]                     

D)         \[\text{6}0{}^\circ \]

Correct Answer: A

Solution :

 In\[\therefore \], AB = AC = 19 cm and BD = DC = 6 cm. In\[\text{224}=\text{12}0\times \text{1}+\text{1}0\text{4}\], \[\text{12}0=\text{1}0\text{4}\times \text{1}+\text{16}\]            \[\text{1}0\text{4}=\text{16}\times \text{6}+\text{8}\]          \[16=8\times 2+0\] \[\text{256}=\text{8}\times \text{32}+0\]\[3465={{3}^{2}}\times 5\times 7\times 11\] \[\text{546}0=\text{22}\times \text{3}\times \text{5}\times \text{7}\times \text{l3}\]