| DIRECTION: A courier person cycles from a town to a neighbouring sub-urban area to deliver a parcel to a merchant. His distance from the town at different times is shown by the following graph, |
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A) 9 a.m. - 10 a.m.
B) 10 a.m. - 11 a.m.
C) 8 a.m. - 9 a.m.
D) 11 a.m. - 11:30 a.m.
Correct Answer: C
Solution :
Speed during 8 a.m. - 9 a:m. = 10/1 = 10 km/h Speed during 9a.m. -10a.m. = 6/1 = 6km/h Speed during 10a.m. -11a.m. = 3/1 = 3km/h Speed during 11 a.m. - 11:30 a.m. \[=\frac{3}{1/2}=6km/h\]
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