A) Isopropyl chloride
B) Isobutyl chloride
C) n-propyl chloride
D) n-butyl chloride
Correct Answer: A
Solution :
Isopropyl chloride \[C{{H}_{3}}-\underset{\underset{Cl\,}{\mathop{|\,\,\,}}\,}{\overset{\overset{\,}{\mathop{{{2}^{o}}}}\,}{\mathop{CH}}}\,-C{{H}_{3}}\] chlorine atom is attached to \[{{2}^{o}}\]carbon atom.
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