A) 80
B) 75
C) 70
D) 7
Correct Answer: B
Solution :
% of Br \[=\frac{\text{Mass}\,\,\text{of}\,\,Br}{\text{Mass of organic compound}}\times 100\] \[=\frac{80}{109}\times 100=73.39\,%\]or approx. 75%
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