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JEE Main & Advanced Physics Wave Mechanics Question Bank Interference and Superposition of Waves

  • question_answer
    The displacement of the interfering light waves are \[{{y}_{1}}=4\sin \omega \,t\] and \[{{y}_{2}}=3\sin \left( \omega \,t+\frac{\pi }{2} \right)\]. What is the amplitude of the resultant wave  [RPMT 1996; Orissa JEE 2005]

    A)            5    

    B)            7    

    C)            1    

    D)            0

    Correct Answer: A

    Solution :

               Since \[\varphi =\frac{\pi }{2}\] Þ \[A=\sqrt{a_{1}^{2}+a_{2}^{2}}=\sqrt{{{(4)}^{2}}+{{(3)}^{2}}}=5\]


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