A) 2 : 1
B) 4 : 1
C) 9 : 1
D) 10 : 8
Correct Answer: B
Solution :
\[\frac{{{I}_{max}}}{{{I}_{min}}}=\frac{{{\left( \frac{\sqrt{{{I}_{1}}}}{\sqrt{{{I}_{2}}}}+1 \right)}^{2}}}{{{\left( \frac{\sqrt{{{I}_{1}}}}{\sqrt{{{I}_{2}}}}-1 \right)}^{2}}}=\frac{{{\left( \sqrt{\frac{9}{1}}+1 \right)}^{2}}}{{{\left( \sqrt{\frac{9}{1}}-1 \right)}^{2}}}=\frac{4}{1}\]
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