A) 1 : 25
B) 25 : 1
C) 9 : 4
D) 4 : 9
Correct Answer: B
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}+1}{\frac{\sqrt{{{I}_{1}}}}{\sqrt{{{I}_{2}}}}-1} \right)}^{2}}={{\left( \frac{\sqrt{\frac{9}{4}}+1}{\sqrt{\frac{9}{4}}-2} \right)}^{2}}=\frac{25}{1}\]
You need to login to perform this action.
You will be redirected in
3 sec
