JEE Main & Advanced Physics Wave Mechanics Question Bank Interference and Superposition of Waves

  • question_answer
    Two waves                    \[{{y}_{1}}={{A}_{1}}\sin (\omega t-{{\beta }_{1}})\], \[{{y}_{2}}={{A}_{2}}\sin (\omega t-{{\beta }_{2}})\]            Superimpose to form a resultant wave whose amplitude is [CPMT 1999]

    A)            \[\sqrt{A_{1}^{2}+A_{2}^{2}+2{{A}_{1}}{{A}_{2}}\cos ({{\beta }_{1}}-{{\beta }_{2}})}\]

    B)            \[\sqrt{A_{1}^{2}+A_{2}^{2}+2{{A}_{1}}{{A}_{2}}\sin ({{\beta }_{1}}-{{\beta }_{2}})}\]

    C)            \[{{A}_{1}}+{{A}_{2}}\]

    D)            \[|{{A}_{1}}+{{A}_{2}}|\]

    Correct Answer: A

    Solution :

               Phase difference between the two waves is                    \[\varphi =(\omega t-{{\beta }_{2}})=(\omega t-{{\beta }_{1}})=({{\beta }_{1}}-{{\beta }_{2}})\]                    \Resultant amplitude \[A=\sqrt{A_{1}^{2}+A_{2}^{2}+2{{A}_{1}}{{A}_{2}}\cos ({{\beta }_{1}}-{{\beta }_{2}})}\]


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