A) \[{{a}^{2}}+{{b}^{2}}=0\]
B) \[{{b}^{2}}+{{c}^{2}}=0\]
C) \[{{a}^{2}}+{{c}^{2}}=0\]
D) \[{{b}^{2}}+{{d}^{2}}=0\]
Correct Answer: D
Solution :
\[a+ib<c+id,\,\] defined if and only if its imaginary parts must be equal to zero, i.e. \[b=d=0.\]So,\[{{b}^{2}}+{{d}^{2}}=0\].
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