• # question_answer $a+ib>c+id$can be explained only when A) $b=0,c=0$ B) $b=0,d=0$ C) $a=0,c=0$ D) $a=0,d=0$

$a+ib>c+id$, it is defined if and only if imaginary parts must be equal to zero. Therefore $ib=id=0$Þ $b=d=0$  $(\because i\ne 0)$