JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Integral power of iota, Algebraic operations and Equality of complex numbers

  • question_answer
    \[\frac{1-2i}{2+i}+\frac{4-i}{3+2i}=\] [RPET 1987]

    A) \[\frac{24}{13}+\frac{10}{13}i\]

    B) \[\frac{24}{13}-\frac{10}{13}i\]

    C) \[\frac{10}{13}+\frac{24}{13}i\]

    D) \[\frac{10}{13}-\frac{24}{13}i\]

    Correct Answer: D

    Solution :

      \[\frac{1-2i}{2+i}+\frac{4-i}{3+2i}=\frac{(1-2i)(3+2i)+(4-i)(2+i)}{(2+i)(3+2i)}\] \[=\frac{50-120i}{65}=\frac{10}{13}-\frac{24}{13}i\].


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