A) \[x=2,y=3\]
B) \[x=-2,y=\frac{1}{3}\]
C) Both (a) and (b)
D) None of these
Correct Answer: C
Solution :
Given equation \[({{x}^{4}}+2xi)-(3{{x}^{2}}+yi)=(3-5i)+(1+2yi)\] \[\Rightarrow \,\,\,({{x}^{4}}-3{{x}^{2}})+i(2x-3y)=4-5i\] Equating real and imaginary parts, we get \[{{x}^{4}}-3{{x}^{2}}=4\] ......(i) and \[2x-3y=-5\] .....(ii) From (i) and (ii), we get \[x=\pm 2\]and \[y=3,\frac{1}{3}\] Trick: Put \[x=2,y=3\]and then \[x=-2,\]\[y=\frac{1}{3},\] we see that they both satisfy the given equation.
You need to login to perform this action.
You will be redirected in
3 sec
