A) 1
B) \[2i\]
C) \[\alpha -i\beta \,(\alpha ,\beta \,\text{real),}\]
D) \[\left( \frac{3-4ix}{3+4ix} \right)=\]
Correct Answer: B
Solution :
\[{{\left[ \frac{2i}{1+i} \right]}^{2}}={{\left[ \left( \frac{2i}{1+i} \right)\,\left( \frac{1-i}{1-i} \right) \right]}^{2}}={{(i+1)}^{2}}={{i}^{2}}+1+2i=2i\].
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