A) \[{{i}^{4n}}=1\]
B) \[{{i}^{4n-1}}=i\]
C) \[{{i}^{4n+1}}=i\]
D) \[{{i}^{-4n}}=1\]
Correct Answer: B
Solution :
We know that \[{{i}^{2}}=-1\] Þ \[{{({{i}^{2}})}^{2}}={{(-1)}^{2}}=1\Rightarrow \,\,\,\,{{i}^{4n}}={{1}^{n}}\] and therefore \[{{i}^{4n-1}}=-i\]
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