• # question_answer If $(1-i)x+(1+i)y=1-3i,$ then  $(x,y)=$ A) $(2,-1)$ B) $(-2,\,1)$ C) $(-2,-1)$ D) (2, 1)

Solution :

$(1-i)x+(1+i)y=1-3i$$\Rightarrow$ $(x+y)+i\,(-x+y)=1-3\,i$ Equating real and imaginary parts, we get $x+y=1$and$-x+y=-3$;  $\therefore$ $x=2,y=-1$. Thus point is$(2,\,-1)$.

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