JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Integral power of iota, Algebraic operations and Equality of complex numbers

  • question_answer
    Additive inverse of \[1-i\]is

    A) \[0+0i\]

    B) \[-1-i\]

    C) \[-1+i\]

    D) None of these

    Correct Answer: C

    Solution :

    If \[z=x+iy\] is the additive inverse of \[1-i\] then \[(x+iy)+(1-i)=0\] Þ \[x+1=0\], \[y-1=0\]                           Þ \[x=-1\], \[y=1\] \[\therefore \] The additive inverse of \[1-i\]is \[z=-1+i\] Trick: Since \[(1-i)+(-1+i)=0\]

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