A) 6
B) 10
C) - 18
D) - 15
Correct Answer: D
Solution :
\[x=3+i\,\Rightarrow \,\,x-3=i\,\] \[\Rightarrow \] \[\,{{x}^{2}}-6x+10=0\] Þ \[{{x}^{3}}-3{{x}^{2}}-8x+15\] \[=x({{x}^{2}}-6x+10)+3\,({{x}^{2}}-6x+10)-15\] \[=x(0)+3(0)-15=-15\].You need to login to perform this action.
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