A) 16
B) - 16
C) 32
D) - 32
Correct Answer: C
Solution :
\[\because \,{{(1+i)}^{2}}=\,1+{{i}^{2}}+2i=2i\] and \[{{(1-i)}^{2}}=1+{{i}^{2}}-2i=-2i\] \[\Rightarrow {{(1+i)}^{8}}+{{(1-i)}^{8}}={{(2i)}^{4}}+{{(-2i)}^{4}}\]\[={{2}^{4}}({{i}^{4}}+{{i}^{4}})\] \[={{2}^{5}}=32.\]
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