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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Integral power of iota, Algebraic operations and Equality of complex numbers

  • question_answer
    If \[i=\sqrt{-1}\], then \[1+{{i}^{2}}+{{i}^{3}}-{{i}^{6}}+{{i}^{8}}\] is equal to [RPET 1995]

    A) \[2-i\]

    B) 1

    C) 3

    D) \[-1\]

    Correct Answer: A

    Solution :

    \[1+{{i}^{2}}+{{i}^{3}}-{{i}^{6}}+{{i}^{8}}=1-1-i+1+1=2-i\].


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