| Column - I | Column - II |
| (i) The additive inverse of 2 | (a) 0 |
| (ii) The greatest negative integer | (b) -2 |
| (iii) The smallest integer greater than every negative integer | (c) 2 |
| (iv) Sum of predecessor and successor of 1 | (d) - 1 |
A) (i)\[\to \](c), (ii)\[\to \](d), (iii)\[\to \](a), (iv)\[\to \](b)
B) (i)\[\to \](b), (ii)\[\to \](d), (iii)\[\to \](a), (iv)\[\to \](c)
C) (i)\[\to \](c), (ii)\[\to \](d), (iii)\[\to \](b), (iv)\[\to \](a)
D) (i)\[\to \](b), (ii)\[\to \](c), (iii)\[\to \](a), (iv)\[\to \](a)
Correct Answer: A
Solution :
(i) The additive inverse of +2 is -2. (ii) The greatest negative integer is -1. (iii) The smallest integer 0 is greater than every negative integer. (iv) Predecessor and successor of 1 are 0 and 2 respectively. \[\therefore \] Sum = 2 + 0 = 2
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