A) 10.8 cm of Hg
B) 14.9cm of Hg
C) 21.8 cm of Hg
D) 38.8 cm of Hg
Correct Answer: A
Solution :
Given that \[{{P}_{1}}=76cm\] of \[Hg\] (Initial pressure at N.T.P.) \[{{P}_{2}}=?\], \[{{V}_{1}}=5litre\], \[{{V}_{2}}=30+5=35litres\] According to Boyle's law \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\]; \[76\times 5={{P}_{2}}\times 35\] \[{{P}_{2}}=\frac{76\times 5}{35}\]Þ \[{{P}_{2}}=10.8cm\] of \[Hg\]
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