A) 72
B) 6
C) 24
D) 36
Correct Answer: A
Solution :
\[\frac{{{r}_{A}}}{{{r}_{H}}}=\sqrt{\frac{{{M}_{H}}}{{{M}_{A}}}}\] \[=\frac{r}{6r}=\sqrt{\frac{2}{{{M}_{A}}}}\] \[{{M}_{A}}=6\times 6\times 2=72g\]
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