A) 0.5 g of \[{{H}_{2}}\] gas
B) 10 g of \[{{O}_{2}}\] gas
C) 15 L of \[{{H}_{2}}\] gas at STP
D) 5 L of \[{{N}_{2}}\] gas at STP
Correct Answer: C
Solution :
In \[22.4l\] of \[{{H}_{2}}\] maximum number of molecules \[=6.023\times {{10}^{23}}\] In \[1l\] of \[{{H}_{2}}\] maximum number of molecules \[=\frac{6.023\times {{10}^{23}}}{22.4}\] In \[15l\]of \[{{H}_{2}}\] maximum number of molecules \[=\frac{6.023\times {{10}^{23}}}{22.4}\times 15\] \[=4.03\times {{10}^{23}}\] molecules.
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