A) 1 : 4
B) 4 : 1
C) 1 : 8
D) 8 : 1
Correct Answer: A
Solution :
\[{{M}_{1}}=32g\] for \[{{O}_{2}}\], \[{{M}_{2}}=2g\] for \[{{H}_{2}}\] \[\frac{{{r}_{1}}}{{{r}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\]; \[\frac{{{r}_{1}}}{{{r}_{2}}}=\sqrt{\frac{2}{32}}=\sqrt{\frac{1}{16}}=\frac{1}{4}\]
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