A) \[{{O}_{2}}\]
B) CO
C) \[N{{O}_{2}}\]
D) \[C{{O}_{2}}\]
Correct Answer: D
Solution :
Molecular weight = \[\frac{mRT}{PV}=\frac{4.4\times .082\times 273}{1\times 2.24}\] = 44 So the gas should be \[C{{O}_{2}}\]
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