A) 110 K
B) 173 K
C) 373 K
D) 273 K
Correct Answer: C
Solution :
\[\frac{{{r}_{{{N}_{2}}}}}{{{r}_{S{{O}_{2}}}}}=\frac{{{V}_{rms}}{{N}_{2}}}{{{V}_{rms}}S{{O}_{2}}}=\sqrt{\frac{{{T}_{{{N}_{2}}}}}{{{T}_{S{{O}_{2}}}}}.\frac{{{M}_{S{{o}_{2}}}}}{{{M}_{{{N}_{2}}}}}}=\sqrt{\frac{{{T}_{{{N}_{2}}}}}{323}\times \frac{64}{28}}\] \[1.625=\sqrt{\frac{{{T}_{{{N}_{2}}}}}{323}.\frac{16}{7}}\] \[{{T}_{{{N}_{2}}}}=\frac{{{(1.625)}^{2}}\times 323\times 7}{16}={{373}^{o}}K\]
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