A) At the centre of the tube
B) Near the hydrogen chloride bottle
C) Near the ammonia bottle
D) Throughout the length of the tube
Correct Answer: B
Solution :
\[N{{H}_{4}}Cl\] ring will first formed near the \[HCl\] bottle because rate of diffusion of \[N{{H}_{3}}\]is more than that of \[HCl\] because \[{{M}_{N{{H}_{3}}}}:{{M}_{HCl}}=17:36.5)\]. SO \[N{{H}_{3}}\]will reach first to the \[HCl\]bottle & will react there with \[HCl\]to form \[N{{H}_{4}}Cl\] ring
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