A) \[{{20}^{o}}C\]
B) \[{{30}^{o}}C\]
C) 400 K
D) 300 K
Correct Answer: C
Solution :
At constant pressure \[V\propto nT\propto \frac{m}{M}T\] \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{m}_{1}}{{T}_{1}}}{{{m}_{2}}{{T}_{2}}}\therefore \frac{{{T}_{1}}}{{{T}_{2}}}=\frac{{{V}_{1}}}{{{m}_{1}}}\times \frac{{{m}_{2}}}{{{V}_{2}}}=\frac{{{d}_{2}}}{{{d}_{1}}}\]\[\Rightarrow \frac{{{300}^{o}}K}{{{T}_{2}}}=\frac{0.75d}{d}\] \[{{T}_{2}}=\frac{300}{0.75}={{400}^{o}}K\]
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