A) 450 K
B) 600 K
C) 800 K
D) 900 K
Correct Answer: A
Solution :
\[\frac{{{P}_{1}}{{V}_{1}}}{{{n}_{1}}{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{n}_{2}}{{T}_{2}}}\therefore {{T}_{2}}=\frac{{{P}_{2}}}{{{P}_{1}}}\frac{{{V}_{2}}}{{{V}_{1}}}{{T}_{1}}\frac{{{m}_{1}}}{{{m}_{2}}}\] \[=\frac{0.75}{1}\times \frac{1}{1}\times \frac{2}{1}\times {{300}^{o}}K\] \[={{450}^{o}}K\]
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