JEE Main & Advanced Chemistry States of Matter Question Bank Ideal gas equation and Related gas laws

  • question_answer One litre of a gas weighs 2 g at 300 K and 1 atm pressure. If the pressure is made 0.75 atm, at which of the following temperatures will one litre of the same gas weigh one gram [CBSE PMT 1992]

    A)                 450 K    

    B)                 600 K

    C)                 800 K    

    D)                 900 K

    Correct Answer: A

    Solution :

               \[\frac{{{P}_{1}}{{V}_{1}}}{{{n}_{1}}{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{n}_{2}}{{T}_{2}}}\therefore {{T}_{2}}=\frac{{{P}_{2}}}{{{P}_{1}}}\frac{{{V}_{2}}}{{{V}_{1}}}{{T}_{1}}\frac{{{m}_{1}}}{{{m}_{2}}}\]                                 \[=\frac{0.75}{1}\times \frac{1}{1}\times \frac{2}{1}\times {{300}^{o}}K\] \[={{450}^{o}}K\]

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