A) 2
B) 1/2
C) 4
D) ¼
Correct Answer: C
Solution :
\[{{d}_{a}}=2{{d}_{b}}\] ; \[2{{M}_{a}}={{M}_{b}}\] \[PV=nRT=\frac{m}{M}RT\]; \[P=\frac{m}{V}.\frac{RT}{M}=\frac{dRT}{M}\] \[\frac{{{P}_{a}}}{{{P}_{b}}}=\frac{{{d}_{a}}}{{{d}_{b}}}\frac{{{M}_{b}}}{{{M}_{a}}}=\frac{2{{d}_{b}}}{{{d}_{b}}}\times \frac{2{{M}_{a}}}{{{M}_{a}}}=4\]
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